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Scrat [10]
3 years ago
5

A rectangular cake has a length of 13 1/2 inches and a width of 9 inches. How many whole, square pieces of cake with side length

s of 2 1/4 inches can be cut from the cake?
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
7 0
Let’s find the area of the rectangular cake and the square pieces.
I’m going to turn the fractions into decimals since it’s easier for me.
13.5•9
121.5
Now find the area of the square pieces.
2.25•2.25
5.0625
Now divide the area of the cake by the pieces to find how many can fit.
121.5/5.0625
24
So, 24 square pieces can be cut out of the rectangular cake.
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Mrs Brown and Mrs Jones make 4 dozen sandwiches in half an hour in Mrs Jones’ small kitchen. If they had 30 friends in to help,
Pepsi [2]

Answer:

1488 sandwiches in thirty minutes

Step-by-step explanation:

5 0
3 years ago
Part A: Create a system of linear equations with no solution. In two or more complete sentences, explain the specific characteri
Dmitrij [34]
Part A.
You need two equations with the same slope and different y-intercepts.
Their graph is parallel lines. Since the lines do not intersect, there is no solution.

y = 2x + 2
y = 2x - 2

Part B.
We use the first equation as above. For the second equation, we use an equation with different slope. Two lines with different slopes always intersect.

y = 2x + 2
y = -2x - 2

In the second equation, y = -2x - 2. We now substitute -2x - 2 for y in the first equation.

-2x - 2 = 2x + 2

-4x = 4

x = -1

Now substitute -1 for x in the first equation to find y.

y = 2x + 2

y = 2(-1) + 2

y = -2 + 2

y = 0

Solution: x = -1 and y = 0
6 0
3 years ago
let f(x)=2x^2+7x-4/x^3-1 what is the domain,range,roots,end behavior and intersect the y-axis of f(X)
victus00 [196]
Here's the factorization of the equation
f(x) = [ (x+4)(2x-1) ] / [ (x-1)(x^2+x+1) ]

<u>Domain</u>
The domain of a function is the set of input or argument values for which the function is real and defined.
- function domain : x < 1 or x > 1

<u>Range
</u>
<u />Resulting f(x) values: all Real Numbers<u>
</u>
<u>Roots
</u>
x = 1/2 & -4

<u>Axis interception points</u>
x-axis: (1/2, 0) , (-4, 0)
(y-axis): (0, 4)

<u>Asymptotes</u>
Vertical: x = 1
Horizontal: y = 0
3 0
3 years ago
Bertha buys electricity from a company that offers a choice of two tariffs. Both have a daily charge of $0.20 regardless of how
Alenkasestr [34]

Answer: D ( 17/20)

Step-by-step explanation:

The two choices are:

The ‘standard’ tariff charges = $0.10 per unit

The ‘day/night tariff’ = $0.12 per unit for each unit consumed between 06:00 and 22:00 but only $0.05 for each unit consumed between 22:00 and 06:00

The day time is between 22:00 and 06:00

Time = 22 - 6 = 16 hours

Let assume that the charges are unit per hour.

For standard tariff = (16 × 0.10) + 0.2

Standard tariff = 1.6 + 0.2 = 1.8

For day/night = (16 × 0.12) + 0.2

= 1.92 + 0.2

= 2.12

The proportion will be

1.8/2.12 = 17/20 ( approximately)

6 0
3 years ago
The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as
bija089 [108]

Answer:

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(score of the 36 golfers was between 70 and 71)

\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}

P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%

P(70 \leq x \leq 71) = 47.7\%

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

8 0
3 years ago
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