Answer:
Since Darcie wants to crochet a minimum of 3 blankets and she crochets at a rate of 1/5 blanket per day, we can determine how many days she will need to crochet a minimum of 3 blankets following the next steps:
- Finding the number of days needed to crochet one (1) blanket:
\begin{gathered}1=\frac{1}{5}Crochet(Day)\\Crochet(Day)=5*1=5\end{gathered}
1=
5
1
Crochet(Day)
Crochet(Day)=5∗1=5
So, she can crochet 1 blanket every 5 days.
- Finding the number of days needed to crochet three (3) blankets:
If she needs 5 days to crochet 1 blanket, to crochet 3 blankets she will need 15 days because:
\begin{gathered}DaysNeeded=\frac{NumberOfBlankets}{Rate}\\\\DaysNeeded=\frac{3}{\frac{1}{5}}=3*5=15\end{gathered}
DaysNeeded=
Rate
NumberOfBlankets
DaysNeeded=
5
1
3
=3∗5=15
- Writing the inequality
If she has 60 days to crochet a minimum of 3 blankets but she can complete it in 15 days, she can skip crocheting 45 days because:
AvailableDays=60-RequiredDaysAvailableDays=60−RequiredDays
AvailableDays=60-15=45DaysAvailableDays=60−15=45Days
So, the inequality will be:
s\leq 45s≤45
The inequality means that she can skip crocheting a maximum of 45 days since she needs 15 days to crochet a minimum of 3 blankets.
Have a nice day!
Answer:
139
Step-by-step explanation:
Substitute x for 15.
9(15)+4
Then multiply:
135+4
And then add:
139
Answer:
<h2>True the speed S in in Feet/second</h2>
Step-by-step explanation:
In this problem we are required to solve for the speed of an object.
given that the expression to solve for the speed is expressed as
speed= distance/time
given data
distance=100 feet
time=2.5 seconds
substituting our given data into the expression we can solve for speed as
speed (S)=100/2.5
S= 40feet/seconds
upon substituting our data the speed S was found to be 40feet/s
True the speed S in in Feet/second
0.015x+0.03(12000-x)=300
Solve for x
X=4000 at 1.5%
12000-4000=8000 at 3%
Answer:
a = -3.8
b = -2.6
c = 1.7
d = 4.4
e = 1.0
Step-by-step explanation:
In the figure attached, the tables are shown.
In an inverse relationship, any point (x,y) in one table is transformed to (y,x) in the other one. For example, in Table A coordinate (1, 2) is present, then in Table B (the inverse), coordinate (2, 1) must be present.
