2. Which is the absolute value of 9 and -9? А -9 с 9 В 0

Mathematics

2 answers:

Furkat [3]3 years ago

7 0

Answer:

Step-by-step explanation:

9-9=0

-9 is basically symbolizing subtraction

Gnoma [55]3 years ago

6 0

The absolute value of 9 and -9 is B=0

You might be interested in

Help pls I will give 20 points

dalvyx [7]

Answer:

neon-0

oxide- -2

copper-2

tin-0

4 0

4 years ago

Factor 2pq - 5qr + 10r - 4p.

Tresset [83]

The answer is B) <span>(q - 2)(2p - 5r)

</span>2pq - 5qr + 10r - 4p = 2pq - 4p - 5qr + 10r
= 2pq - 4p - (5qr - 10r)
= 2p(q - 2) - 5r(q - 2)
= (q - 2)(2p - 5r)

5 0

3 years ago

Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers

Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the $x^2$ coefficient is 1, i.e. the equation is written like $x^2+bx+c=0$ , then you can say the following about the coefficients b and c:

$b$ is the opposite of the sum of the roots
$c$ is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

$4+(-2) = 4-2 = 2 \implies b = -2$
$4 \cdot (-2) = -8 \implies c = -8$

So, the equation is $x^2-2x-8=0$

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

$\dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}$
$\dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}$