Express 108 as a product of it prine factors

Mathematics

1 answer:

kompoz [17]2 years ago

4 0

Answer:

2 x 2 x 3 x 3 x 3

Step-by-step explanation:

set up a factoring tree.

108

9 12

3 3 3 4

2 2

You might be interested in

5*10 divided by 30 -10

sp2606 [1]

The answer to your question would be -25/3

As decimal -8.333333

4 0

2 years ago

2x+y=9 8x+4y=36 It doesn’t make sense can anyone help!!

denis-greek [22]

Step-by-step explanation:

noob hahahahahhahahahaha

8 0

2 years ago

Use series to verify that <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{

SVETLANKA909090 [29]

$y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\$

$\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\$

This shows that $y' = y$ is true when $y = e^x$

-----------------------

Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.

6 0

2 years ago

Suppose a jar contains 15 red marbles and 19 blue marbles. If you reach in the jar and pull out 2 marbles at random at the same

Kay [80]

Answer: $\bold{\dfrac{35}{187}}$

Step-by-step explanation:

1st marble and 2nd marble

$\dfrac{15\ red}{34\ total}$ $\times$ $\dfrac{14\ red}{33\ total}$ $=\dfrac{15\times 14}{34\times 33}=\dfrac{5\times 7}{17\times 11}= \boxed{\dfrac{35}{187}}$