Answer:
-35/6
Step-by-step explanation:
We need to find the value of x , And the given pair of Rational numbers are equal.
<u>Question</u><u> </u><u>(</u><u>I)</u><u> </u><u>:</u><u>-</u><u> </u>
→ 3/4 = 7/x
→ 7/x = 3/4
→ 1/x = 3/4 × 1/7
→ 1/x = 3/28
→ x = 28/3
<u>Question</u><u> (</u><u>ii)</u><u> </u><u>:</u><u>-</u><u> </u>
→ x/7 = -5/6
→ x = -5/6 × 7
→ x = -35/6
<h3>
• Hence the value of x is -35/6 .</h3>
2 1/10 because the 1 in 2.1 is in the tenth place
Answer:
18 units
Step-by-step explanation:
So let's list out the sides.
for the first square let's just call them x
for the second square then they would be x+5 and x-3
So let's write out their areas we will cal the area of the first one z
x*x = z
(x+5)*(x-3) = z+21
since z = x^2 we can set up the second equation as a quadratic.
(x+5)*(x-3) = x^2 + 21
x^2 - 3x + 5x - 15 = x^2 + 21
But look, the x^2s cancel out
2x - 15 = 21
2x = 36
x = 18
Test it out and see if it fits the description, And if you don't understand anything just let me know so I can explain more.
Answer:
Least positive integer divisible by the numbers 2, 4, and 7 is 28
Step-by-step explanation:
We can find the least positive integer divisible by the numbers 2, 4, and 7 by taking the LCM
First lets List all prime factors for each number.
Prime Factorization of 2
2 is prime => 
Prime Factorization of 4 is:
2 x 2 => 
Prime Factorization of 7 is:
7 is prime => 
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 7
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 7 = 28