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lutik1710 [3]
3 years ago
9

A vase can hold 9 flowers. If a florist had 878 flowers she wanted to put equally into vases, how many flowers would be in the l

ast vase that isn't full?
Mathematics
2 answers:
Bingel [31]3 years ago
7 0
878/9=97 vase full of flowers. 
97*9=873
878-873=5 flowers left in the vase
zavuch27 [327]3 years ago
3 0
There are 5 flowers in the last vase because you divide 878 by 9 and get 97 and then you have 5 leftover
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EMERGENCY!!! What is the volume of the following rectangular prism
Ne4ueva [31]

Answer:

42

Step-by-step explanation:

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3 years ago
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pentagon [3]

Answer: 1.=c

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3 0
3 years ago
Given: ΔPSQ, PS = SQ
horrorfan [7]
<h2>Answer:</h2>

To solve this problem we will use Heron's formula:

A=\sqrt{s(s-a)(s-b)(s-c)}

Where a, \ b \ and \ c are the side lengths of the triangle and s is the semiperimeter (half the perimeter of the triangle). We know that:

Perimeter \ P=\triangle PSQ=PS+PQ+SQ: \\ \\ \triangle PSQ=P=50 \\ \\ Semiperimeter \ s: \\ \\ s=\frac{P}{2}=25

Also:

(I) \ PS=SQ \\ \\ (II) \ SQ-PQ = 1 \\ \\ (III) \ PS+PQ+SQ=50 \\ \\ \\ (I) \ into \ (III): \\ \\ SQ+PQ+SQ=50 \\ \\ \therefore (IV) \ 2SQ+PQ=50 \\ \\ From \ (II): \\ \\ PQ=SQ-1 \\ \\ (II) \ into \ (IV): \\ \\ 2SQ+(SQ-1)=50 \\ 3SQ-1=50 \\ 3SQ=51 \\ \\ \boxed{SQ=17} \\ \\ \boxed{PS=17} \\ \\ PQ=SQ-1=17-1 \therefore \boxed{PQ=16}

Finally:

A=\sqrt{s(s-a)(s-b)(s-c)} \\ \\ A=\sqrt{s(s-PS)(s-SQ)(s-PQ)} \\ \\ A=\sqrt{s(s-17)(s-17)(s-16)} \\ \\ A=\sqrt{25(25-17)(25-17)(25-16)} \\ \\ \boxed{A=120}

7 0
3 years ago
Does anyone know the answer
Alex_Xolod [135]

Answer:x = 12,5

using thales's theorem, we have:

\frac{15}{15+36}=\frac{20}{6x-7}\\\\ 6x-7=\frac{20.(15+36)}{15}=68\\\\x = \frac{68+7}{6}=12.5

Step-by-step explanation:

8 0
3 years ago
The vertices of quadrilateral MNPQ are M(−3,−2),N(−1,4),P(2,4), and Q(4,−2). Translate quadrilateral MNPQ using the vector ⟨3,−4
muminat

Answer:

see explanation

Step-by-step explanation:

A translation using the vector < 3, - 4 > , means

Add 3 to the x- coordinate and subtract 4 from the y- coordinate, so

M (- 3, - 2 ) → M' (- 3 + 3, - 2 - 4 ) → M' (0, - 6 )

N (- 1, 4 ) → N' (- 1 + 3, 4 - 4 ) → N' (2, 0 )

P (2, 4 ) → P' (2 + 3, 4 - 4 ) → P' (5, 0 )

Q (4, - 2 ) → Q' (4 + 3, - 2 - 4 ) → (7, - 6 )

4 0
3 years ago
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