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2 years ago

What is 103% of 127?

Mathematics

1 answer:

Firdavs [7]2 years ago

3 0

Answer:

130.81

Step-by-step explanation:

127 ⋅ ( 103/ 100 ) =130.81

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Gnoma [55]

Answer:

your mom

Step-by-step explanation:

3 0

2 years ago

Which is an equivalent expression for 21a+35?

ki77a [65]

Answer:

7(3a + 5)

Step-by-step explanation:

Rewrite 21 as 7 · 3

Rewrite 35 as 7 · 5

Therefore,

⇒ 21a + 35 = 7 · 3a + 7 · 5

Factor out common term 7:

⇒ 7 · 3a + 7 · 5 = 7(3a + 5)

5 0

2 years ago

PLEASE HELP ME! TIMED!

erica [24]

Answer:

1.6-5 2. 42 3. 36/66

Step-by-step explanation:

6 0

2 years ago

Solve the following system of equations using the substitution method.

sergey [27]

Answer:

y=1; x=2

Step-by-step explanation:

Substitution:

x=2y

2x+5y=9

=> if x=2y, plug in the x value into other equation, so

----------------------------------------------------------------------------

2(2y)+5y=9

4y+5y=9

9y=9

y=1

You have the Y value, so now solve for X

-----------------------------------------------------------------------

plug in y value to x=2y

so x=2(1)

x=2

5 0

2 years ago

Simplify: cos2x-cos4 all over sin2x + sin 4x

GrogVix [38]

Answer:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

Step-by-step explanation:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}$

Apply formula:

$\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$ and

$\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$

We get:

$=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}$

$=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}$

$=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}$

$=\frac{\sin\left(x\right)}{\cos\left(x\right)}$

$=\tan\left(x\right)$

Hence final answer is

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

6 0

2 years ago