The equations
and
are really the same, we're just setting 
, or 
.
So we get
Step-by-step answer:
We are looking at the coefficient of the 22nd term of (x+y)^25.
Following the sequence, first term is x^0y^25, second term is x^1y^24, third term is x^2y^23...and so on, 22nd term is x^21y^4.
The twenty-second term of (x+y)^25 is given by the binomial theorem as
( 25!/(21!4!) ) x^21*y^4
=25*24*23*22/4! x^21y^4
= 12650 x^21 y^4
The coefficient required is therefore 12650, for a binomial with unit valued coefficients.
For other binomials, substitute the values for x and y and expand accordingly.
Question would have been more clearly stated if the actual binomial was given, as commented above.
Answer:
-7.1
Step-by-step explanation:
Answer:
2 3/8
Step-by-step explanation:
If what you're saying it 3 1/8 - 3/4 then...
3 1/8 - 3/4
3 1/8 - 6/8
25/8 - 6/8
19/8
2 3/8
