
<h2>
Explanation:</h2>
The nth term of an arithmetic series (
) and the sum of an arithmetic series (Sum), for n terms, can be found as:
![a_{n}=a_{1}+d(n-1) \\ \\ Sum=\frac{n}{2}[2a_{1}+(n-1)d] \\ \\ \\ Where: \\ \\ a_{1}:First \ term \\ \\ d:Common \ difference \\ \\ n=Number \ of \ term](https://tex.z-dn.net/?f=a_%7Bn%7D%3Da_%7B1%7D%2Bd%28n-1%29%20%5C%5C%20%5C%5C%20Sum%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a_%7B1%7D%2B%28n-1%29d%5D%20%5C%5C%20%5C%5C%20%5C%5C%20Where%3A%20%5C%5C%20%5C%5C%20a_%7B1%7D%3AFirst%20%5C%20term%20%5C%5C%20%5C%5C%20d%3ACommon%20%5C%20difference%20%5C%5C%20%5C%5C%20n%3DNumber%20%5C%20of%20%5C%20term)
So, in this exercise:
![a_{1}=a=9 \\ \\ d=4 \\ \\ n=16 \\ \\ \\ Sum=\frac{16}{2}[2(9)+(16-1)4] \\ \\ Sum=8[18+(15)4] \\ \\ Sum=8[18+60] \\ \\ Sum=8[78] \\ \\ \boxed{Sum=624}](https://tex.z-dn.net/?f=a_%7B1%7D%3Da%3D9%20%5C%5C%20%5C%5C%20d%3D4%20%5C%5C%20%5C%5C%20n%3D16%20%5C%5C%20%5C%5C%20%5C%5C%20Sum%3D%5Cfrac%7B16%7D%7B2%7D%5B2%289%29%2B%2816-1%294%5D%20%5C%5C%20%5C%5C%20Sum%3D8%5B18%2B%2815%294%5D%20%20%5C%5C%20%5C%5C%20Sum%3D8%5B18%2B60%5D%20%5C%5C%20%5C%5C%20Sum%3D8%5B78%5D%20%5C%5C%20%5C%5C%20%5Cboxed%7BSum%3D624%7D)
<h2>Learn more:</h2>
Missing numbers in triomino: brainly.com/question/10510270
#LearnWithBrainly
Answer: Answer is C
Step-by-step explanation:
There is not enough samples.
Answer:
The correct option is option D
Step-by-step explanation:
The volume of a pyramid is:
V=1/3(B)(H)
Where
B:Base = s^2
H:Height = 2/3s
Then:
V=1/3(B)(H) = 1/3(s^2)(2/3s) = 2/9s^3
The correct option is option D
Answer:

Step-by-step explanation:
Given equation of line is:
2x-3y=13
We will convert the equation of line in point-slope form to find the slope of the line
Let
m_1 be the slope of the line
So,
2x-3y=13
-3y= -2x+13
Dividing both sides by -3
(-3y)/(-3)=(-2x)/(-3)+13/(-3)
y=(2/3)x-13/3
The co-efficient of x is the slope of the line.
So,
m_1=2/3
Let
m_2 be the slope of second line
As we know that product of slopes of two perpendicular line is -1
m_1 m_2= -1
2/3*m_2= -1
m_2= -1*3/2
m_2= -3/2
So m2 is the slope of the line perpendicular to given line.
The standard equation of a line is
y=mx+b
To find the equation of line through (-6,5), put the point and slope in the given form and solve for b
5= -3/2 (-6)+b
5=18/2+b
5=9+b
b=5-9
b= -4
Putting the values of slope and b, we get
