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Alexeev081 [22]
3 years ago
14

A pyramid has a square base with side s. The height of the pyramid is 2/3 that of its side. What is the expression for the volum

e of the pyramid?
A) V = 2s^2
B) V = 2s^3
C) V = 2/3s^2
D) V = 2/9s^3
E) V = 1/3s^3


Random answers will be reported!
Mathematics
1 answer:
Temka [501]3 years ago
8 0

Answer:

The correct option is option D

Step-by-step explanation:

The volume of a pyramid is:

V=1/3(B)(H)

Where

B:Base = s^2

H:Height = 2/3s

Then:

V=1/3(B)(H) = 1/3(s^2)(2/3s) = 2/9s^3

The correct option is option D

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The x-axis and y-axis are two lines that create the coordinate plane. The x-axis is a horizontal line and the y-axis is a vertic
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4 0
3 years ago
✨ B R A I N L I E S T
miv72 [106K]

1

:x

2

+y

2

−6x−9y+13=0

(x−3)

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+(y−

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2

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65

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=

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Equation of another circle-

S

2

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2

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2

−2x−16y=0

(x−1)

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+(y−8)

2

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(x−1)

2

+(y−8)

2

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Here,

r

2

=

65

C

2

=(1,8)

Distance between the centre of two circles-

C

1

C

2

=

(3−1)

2

+(8−

2

9

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2

C

1

C

2

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4+

4

49

=

2

65

∣r

2

−r

1

∣=

∣

∣

∣

∣

∣

∣

65

−

2

65

∣

∣

∣

∣

∣

∣

=

2

65

∵C

1

C

2

=∣r

1

−r

2

∣

Thus the two circles touches each other internally.

Since the circle touches each other internally. The point of contact P divides C

1

C

2

externally in the ratio r

1

:r

2

, i.e.,

2

65

:

65

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Therefore, coordinates of P are-

⎝

⎜

⎜

⎜

⎜

⎜

⎛

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1(1)−2(3)

,

1−2

1(8)−2(

2

9

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⎠

⎟

⎟

⎟

⎟

⎟

⎞

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Therefore,

Equation of common tangent is-

S

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2

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(5x+y−6(

2

x+5

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2

y+1

)+13)−(5x+y−2(

2

x+5

)−16(

2

y+1

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2

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4x−7y−13=0

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4 0
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Step-by-step explanation:

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