Question

Find the distance between (-9,-5) and (4,-3)

Answer 1

The distance between the points (-9, -5) and (4, -3) is 13.153 units approximately

Solution:

Given, two points are (-9, -5) and (4, -3).

We need to find the distance between above two points.

We know that, distance between two points $P\left(x_{1}, y_{1}\right) \text { and } Q\left(x_{2}, y_{2}\right)$ is given by:

$d(P, Q)=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

$\text { here, } x_{1}=-9, y_{1}=-5, x_{2}=4 \text { and } y_{2}=-3$

$\begin{array}{l}{\text { distance }=\sqrt{(4-(-9))^{2}+(-3-(-5))^{2}}=\sqrt{(4+9)^{2}+(5-3)^{2}}} \\\\ {=\sqrt{(13)^{2}+(2)^{2}}=\sqrt{169+4}=\sqrt{173}=13.152946}\end{array}$

Hence the distance between points is 13.153 units approximately

Answer 2

Answer:

15.13

Step-by-step explanation:

In the attached file