Let's do subtraction by first starting with the ones place and then the tenths place of the subtrahend.
45-4=41; 44, 43, 42, 41
41-.5= 40.5; 40.9, 40.8, 40.7, 40.6, 40.5
45-4.5=40.5
We can check by using addition.
40.5+4.5=
44+1=
45
61.67$ because you round the 7 up to the nearest hundredth
Find three consecutive odd integral such that the sum of seven times the smallest and twice the largest is -91
Answer:
There would be an overall 25% decrease
Step-by-step explanation:
Because -75 + 50 = -25
