That is the centroid.
The point where the lines from each vertex of the triangle to the midpoints of the opposite sides intersect.
C=2pir
20pi=2pir
20pi/2pi=2pir/2pi
R=10
Height=10/2=5
Two circles surface areas is
2*pir^2
2pi10^2
2*100pi
200pi
The cylindrical part is
2pirh
2pi*10*5
100pi
Add 100pi+200pi=300pi
Answer:
1
Step-by-step explanation:
use PEMDAS=
2+6=12
12x2=24
48/24=2
2-1= 1
