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Likurg_2 [28]
3 years ago
5

Will mark brainliest, I'm having some trouble (question in attachment)

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
4 0

Answer: 45b^4/32

Step-by-step explanation: First multiply the two fractions

15b^3y(3b)/8y x 4

Multiply 3 by 15

45b^3yb/8y x 4

Raise b to power of 1

45(b^1b^3)y/8y x 4

Use power rule to combine exponents

45b^1+3 y/8y x 4

Simplify

45b^4y/32y

Cancel common factor of y

45b^4/32

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It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig
Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let \mu denotes the average hours of sleep per night.

As per given , we have

H_0:\mu=7\\H_a:\mu

, since H_a is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : \overline{x}=7.24

Sample  standard deviation : s= 1.93

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

i.e.  t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58

For significance level \alpha=0.05 and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= t_{\alpha, df}=t_{0.05,21}=- 1.7207

Decision : Since the test statistic value (0.58) > critical value  1.7207, it means we are failed to reject the null hypothesis .

[Note : When |t_{cal}|>|t_{cri}|, then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

6 0
2 years ago
What is the radius of 706.5 ft in circle ft
mel-nik [20]
If you mean "what is the radius in feet of a circle that is 706.5 ft in diameter", then the answer is 353.25 ft.
Otherwise, I o no.
4 0
3 years ago
A chord is 10cm from the centre of a circle of radius 15cm. Find the length of the chord.
almond37 [142]

Answer: 21.44 cm

Step-by-step explanation:

Given

Radius r=15 cm

distance of chord from the center is 10 cm

From the figure, the length of the chord is AC

Applying Pythagoras

\Rightarrow AO^2=OB^2+AB^2\\\Rightarrow AB^2=15^2-10^2\\\Rightarrow AB^2=225-100=115\\\Rightarrow AB=\sqrt{115}=10.72\ cm

The length of the chord is AC=2AB=21.44\ cm

5 0
3 years ago
What is the area of this composite shape?
grandymaker [24]

(29-22)*26+(26-21)*22

Cut the figure into 2 then find the unknown lengths to find each part. Add them together, and you'll get the answer.

4 0
3 years ago
Write the decimal 1.0056 in word form
Ludmilka [50]

Answer:

one and fifty six hundred thousandths

4 0
3 years ago
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