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2 years ago

Find the standard deviation of the data set shown. Round your answer to the nearest tenth.

Mathematics

2 answers:

Degger [83]2 years ago

7 0

Mark Brainliest Please

Answer:

Answer is gicen in the image attached.

Step-by-step explanation:

Standard deviation (SD) measured the volatility or variability across a set of data. It is the measure of the spread of numbers in a data set from its mean value and can be represented using the sigma symbol (σ). The following algorithmic calculation tool makes it easy to quickly discover the mean, variance & SD of a data set.

For more help check Khan academy video

https://www.khanacademy.org/math/statistics-probability/displaying-describing-data/sample-standard-deviation/v/sample-standard-deviation-and-bias

rosijanka [135]2 years ago

5 0

I really don’t know the answer nesxt time

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3 years ago

What is the sum of the following infinite series?<br> 5+ 15/7 + 45/49 + 135/343

liberstina [14]

Answer:

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Step-by-step explanation:

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3 years ago

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tensa zangetsu [6.8K]

Multiply $Q\cdot P$ , quantity and price,

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3 years ago

Read 2 more answers

Problem 4: Solve the initial value problem

pishuonlain [190]

Separate the variables:

$y' = \dfrac{dy}{dx} = (y+1)(y-2) \implies \dfrac1{(y+1)(y-2)} \, dy = dx$

Separate the left side into partial fractions. We want coefficients a and b such that

$\dfrac1{(y+1)(y-2)} = \dfrac a{y+1} + \dfrac b{y-2}$

$\implies \dfrac1{(y+1)(y-2)} = \dfrac{a(y-2)+b(y+1)}{(y+1)(y-2)}$

$\implies 1 = a(y-2)+b(y+1)$

$\implies 1 = (a+b)y - 2a+b$

$\implies \begin{cases}a+b=0\\-2a+b=1\end{cases} \implies a = -\dfrac13 \text{ and } b = \dfrac13$

So we have

$\dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = dx$

Integrating both sides yields

$\displaystyle \int \dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = \int dx$

$\dfrac13 \left(\ln|y-2| - \ln|y+1|\right) = x + C$

$\dfrac13 \ln\left|\dfrac{y-2}{y+1}\right| = x + C$

$\ln\left|\dfrac{y-2}{y+1}\right| = 3x + C$

$\dfrac{y-2}{y+1} = e^{3x + C}$

$\dfrac{y-2}{y+1} = Ce^{3x}$

With the initial condition y(0) = 1, we find

$\dfrac{1-2}{1+1} = Ce^{0} \implies C = -\dfrac12$

so that the particular solution is

$\boxed{\dfrac{y-2}{y+1} = -\dfrac12 e^{3x}}$

It's not too hard to solve explicitly for y; notice that

$\dfrac{y-2}{y+1} = \dfrac{(y+1)-3}{y+1} = 1-\dfrac3{y+1}$

Then

$1 - \dfrac3{y+1} = -\dfrac12 e^{3x}$

$\dfrac3{y+1} = 1 + \dfrac12 e^{3x}$

$\dfrac{y+1}3 = \dfrac1{1+\frac12 e^{3x}} = \dfrac2{2+e^{3x}}$

$y+1 = \dfrac6{2+e^{3x}}$

$y = \dfrac6{2+e^{3x}} - 1$

$\boxed{y = \dfrac{4-e^{3x}}{2+e^{3x}}}$

7 0

2 years ago

PLZ PLZ WITH EXPLANATION

Vadim26 [7]

Answer:

For the first 2 pages, you will want to count how many sides and angles for the stated figure above. Then you want to figure out what other figures that are related to the figure stated above. i.e. a square is a rectangle but not all rectangles are squares. On the last page you want to figure out what is the figure's name and other names that are related/same on the figure's original name. And lastly for part II you want to do the same thing for page 1 and 2, but instead you want to compare and contrast the 2 figures stated above. i.e. Parallelograms and Trapezoids.

Step-by-step explanation:

Hope this helps! :)

8 0

2 years ago