Answer:
essentially, in these problems, youre finding the square root of each number. the square root should be a decimal thats in between two other numbers, and those will be the integers that the value of the square root is between. unless the value is exactly a number and a half, it will be closer to one integer than the other. the work is below.
square root of:
59= 7.68
68= 8.246
78= 8.83
93= 9.64
104= 10.198
124= 11.14
33= 5.74
185= 13.6
215= 14.66
these are just the square roots. but, as you can see, each number is between two other whole numbers on a number line. So, just write down what those numbers are.
7.68 is between 7 and 8
8.246 is between 8 and 9
8.83 is between 8 and 9
9.64 is between 9 and 10
10.198 is between 10 and 11
11.14 is between 11 and 12
5.74 is between 5 and 6
13.6 is between 13 and 14
14.66 is between 14 and 15
so, we know thw numbers that each decimal is between, but we have to find which one each is cloest to. in order to do that, just know that if the decimal is more than .5 its closer to the larger number, and its its less than .5, its closer to thw smaller number.
7.68 is closer to 8
8.246 is closer to 8
8.83 is closer to 9
9.64 is closer to 10
10.198 is closer to 10
11.14 is closer to 11
5.74 is closer to 6
13.6 is closer to 14
14.66 is closer to 15
5 to the power of 1,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000.
UNO [17]
Answer:
60000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
Step-by-step explanation:
Answer:
A system has infinitely many solutions when it is consistent and the number of variables is more than the number of nonzero rows in the rref of the matrix. For example if the rref is ��has solution set (4-3z, 5+2z, z) where z can be any real number.
Answer: The average of the first two test scores is 97.
Step-by-step explanation: Given that Kristie has taken five tests in science class. The average of all five of Kristie's test scores is 94 and the average of her last three test scores is 92.
We are to find the average score of her first two tests.
Let a1, a2, a3, a4 and a5 be teh scores of Kristle in first , second, third, fourth and fifth tests respectively.
Then, according to the given information, we have
and
Subtracting equation (ii) from equation (i), we get
Thus, the average of the first two test scores is 97.
The angles ACD and Angle ABE are congruent so there measure is equal.
3x+14=50
3x= 50-14
3x= 36
X= 36/3=12