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jonny [76]
3 years ago
12

the questipn is: Given segment AB with endpoint (-2,-2) and (8,4), what is the coordinate of the midpoint?​

Mathematics
1 answer:
Nataly [62]3 years ago
6 0

Answer:

(3,1)

Step-by-step explanation:

If you plot both of the points on a graph you get another straight line.

When you connect the dots you get 3,1 as the midpoint of the two segments :))

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Please help me!!!!!
chubhunter [2.5K]

Answer:

y = - \frac{2}{5} (x - 5)² + 7

Step-by-step explanation:

The equation of a quadratic in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (5, 7 ) , then

y = a(x - 5)² + 7

To find a substitute (10, - 3 ) into the equation

- 3 = a(10 - 5)² + 7 ( subtract 7 from both sides )

- 10 = 5²a = 25a ( divide both sides by 25 )

\frac{-10}{25} = a , that is

a = - \frac{2}{5}

y = - \frac{2}{5} (x - 5)² + 7 ← in vertex form

8 0
2 years ago
Please help ASAP!!!!
PilotLPTM [1.2K]

Answer:

2/25

Step-by-step explanation:^2 = 1/25

Cubic Root 8 = cubic root = 2^3 = 2

(1/25)*(2) = 2/25

6 0
2 years ago
Aviation:
kolezko [41]

Change in altitude:

42,000 - 18,000 = 24,000 feet

Rate of change  = 24,000 feet / 12 minutes = 2,000 feet per minute

Because the plane was going down, the rate of change would be negative.

The rate would be -2,000 feet per minute.

8 0
2 years ago
Which relation is a function?
sashaice [31]

Answer:

Step-by-step explanation:

B. for it to be a proper function, it must pass the vertical line test (meaning, if you were to fill a continuous line between each of the dots, and then drew a string vertical line down at any point along the function, that vertical line cannot intersect with the function line more than once.

A, would fail the vertical line test, C< and D would also fail, as a vertical line would intersect/cross the function line more than once.

7 0
3 years ago
13
zepelin [54]

Answer:

The required equation is: \mathbf{f(x)=\frac{3}{4}x-\frac{29}{4}}

Step-by-step explanation:

We need to find equation from the table given

x     f(x)

3     -5

7     -2

11     1

15    4

We can write equation in the form of y=mx+b

where m is slope and b is y-intercept.

Finding Slope

We can used the slope formula to find slope: Slope=\frac{y_2-y_1}{x_2-x_1}

From the table we have: x_1=3, y_1=-5, x_2=7, y_2=-2

Putting values and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-2-(-5)}{7-3} \\Slope=\frac{-2+5}{7-3}\\Slope=\frac{3}{4}

So, we get slope m=\frac{3}{4}

Now, finding y-intercept

Using the slope m=\frac{3}{4} and point (3,-5) we can find y-intercept

y=mx+b\\-5=\frac{3}{4}(3)+b\\-5=\frac{9}{4}+b\\b=-5-\frac{9}{4}\\b=\frac{-5*4-9}{4}\\b=\frac{-20-9}{4}\\b=\frac{-29}{4}

The y-intercept is b=\frac{-29}{4}

So, the equation having slope m=\frac{3}{4} and y-intercept b=\frac{-29}{4} will be:

y=mx+b\\y=\frac{3}{4}x-\frac{29}{4}

The required equation is: \mathbf{f(x)=\frac{3}{4}x-\frac{29}{4}}

6 0
2 years ago
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