Answer:
The equivalent statement is
⇒ 2nd answer
Step-by-step explanation:
* Lets explain how to solve the problem
- Any root can be a fraction power
- Ex: 
![\sqrt[3]{a}=a^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[4]{a}=a^{\frac{1}{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D)
![\sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
* The expression is 
∵
can be written as 
∵ ![(80)^{\frac{1}{4}}=\sqrt[4]{80}](https://tex.z-dn.net/?f=%2880%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%5Csqrt%5B4%5D%7B80%7D)
∴
= ![(\sqrt[4]{80})^{x}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B80%7D%29%5E%7Bx%7D)
* The equivalent statement is ![(\sqrt[4]{80})^{x}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B80%7D%29%5E%7Bx%7D)
Answer:

Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
∠ PQS + ∠SQR = ∠ PQR , substitute values
13x + 4 + 10x - 1 = 141 , that is
23x + 3 = 141 (subtract 3 from both sides )
23x = 138 ( divide both sides by 23 )
x = 6
Thus
∠ PQS = 13x + 4 = 13(6) + 4 = 78 + 4 = 82°
∠ SQR = 10x - 1 = 10(6) - 1 = 60 - 1 = 59°
No, Shani is not right.
The 1st customer to get popcorn and apple juice is the 18th customer.
She missed that 18 is a common multiple of 6 & 9
Volume= whd
= (48)(34)(12)
= 19,584 yards³