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3 years ago

8

Please help need a 100

1 answer:

aivan3 [116]3 years ago

4 0

I'd have to say it's A. Please don't blame me if I'm wrong. :)

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Derivatives of inverse trigonometric functions please explain answers

Jobisdone [24]

I'll explain how to do the first one:-

y = cos-1(x2)

This can be described as ' a function of a function' x^2 is a function of x and cos-1(x^2) is a function of x^2.

We need to apply the chain rule.

Personally I find this easier to understand if i let u = x^2, so

If y = f(u) and u is a function of x then

dy/dx = dy/ du * du/dx

Here u = x^2 and y = cos-1(u)

du/dx = 2x

so dy/dx = d(cos-1(x^2) dx = dy/du * du/dx

= -1 / √(1 - u^2) * 2x

= -2x / √(1 - u^2)

= -2x / √(1 - (x^2)^2)

= -2x / √(1 - x^4)

I hope this helps. but if not. you might like to employ the formulae in the question - The square boxes contain the 'u' s in my answer. These formulae are equivalent to my explanation.

6 0

3 years ago

An inequality is a mathematical statement that ________________the relative values of two expressions.

Natali [406]

Answer:

An inequality is a mathematical statement that EXPLAINS the relative values of two expressions.

8 0

3 years ago

Read 2 more answers

Pls I need help !!!!

harkovskaia [24]

Answer:I have an answer a good answer

S H R E K I S L O V E

Step-by-step explanation:

Hail Shrek

5 0

3 years ago

Help please<3 for all questions with solutions plz

antiseptic1488 [7]

Answer:

a) $h = -\frac{7}{4}$ , b) $h = f\,\circ\,g (-5) = \frac{3}{2}$ , c) $h = g\,\circ\,f (-2) = \frac{3}{8}$

Step-by-step explanation:

We proceed to solve each exercise below:

a) $f(-2) +3\cdot g(0)$

$h = \frac{2\cdot (-2)}{3\cdot (-2)+5}+3\cdot \left(\frac{3}{0+4} \right)$

$h = \frac{-4}{-6+5} +3\cdot \left(\frac{3}{4} \right)$

$h = -4+\frac{9}{4}$

$h = \frac{-16+9}{4}$

$h = -\frac{7}{4}$

b) $h = f\,\circ \,g (-5)$

$h = f\,\circ\,g (x) = \frac{\frac{6}{x+4} }{\frac{9}{x+4}+5 }$

$h = f\,\circ\,g (x)= \frac{\frac{6}{x+4} }{\frac{9+5\cdot (x+4)}{x+4} }$

$h = f\,\circ\,g (x) = \frac{6}{29+5\cdot x}$

$h = f\,\circ\,g (-5) = \frac{6}{29+5\cdot (-5)}$

$h = f\,\circ\,g (-5) = \frac{3}{2}$

c) $h = g\,\circ\,f(-2)$

$h = g\,\circ \, f (x) = \frac{3}{\frac{2\cdot x}{3\cdot x + 5} + 4 }$

$h = g\,\circ\,f (x) = \frac{3}{\frac{2\cdot x +4\cdot (3\cdot x +5)}{3\cdot x +5 } }$

$h = g\,\circ \,f (x) = \frac{3\cdot (3\cdot x +5)}{2\cdot x +12\cdot x +20}$

$h = g\,\circ\,f(x) = \frac{9\cdot x +15}{14\cdot x +20}$

$h = g\,\circ\,f(-2) = \frac{9\cdot (-2)+15}{14\cdot (-2)+20}$

$h = g\,\circ\,f (-2) = \frac{-3}{-8}$

$h = g\,\circ\,f (-2) = \frac{3}{8}$

6 0

3 years ago

Enter a recursive rule for the geometric sequence.

Jlenok [28]

Answer:

$x_{n} = 5 \ * \ (-2)^{n-1}$

Step-by-step explanation:

Given the geometric sequence:

5, −10, 20, −40, ...

The first term is a = 5

And the common ratio = r = -10/5 = -2

The general rule of geometric sequence is

$x_{n} = a \ * \ r^{n-1}$

So, the rule for the given geometric sequence is:

$x_{n} = 5 \ * \ (-2)^{n-1}$

8 0

3 years ago