Question

For each function shown:

Answer 1

Answer:

Step-by-step explanation:

Function (1) has been given as,

y = 0.5 + 3x

Table for the points on this function,

x        0         1          2          3         4

y       0.5     3.5       6.5      9.5     12.5

$y_2-y_1=3.5-0.5=3$

$y_3-y_2=6.5-3.5=3$

There is a common difference of 3 each successive term of y from the previous term.

Therefore, starting point of the function is (0, 0.5)

There is a linear growth of 3 with the increase in the value of x.

Function (2),

y = 3(0.5)ˣ

x       0         1          2           3           4

y       3        1.5     0.75     0.375   0.1875

Starting point of the function will be (0, 3)

There is a common ratio of 0.5 in each successive term to the previous term.

$\frac{y_2}{y_1}=\frac{1.5}{3}=0.5$

$\frac{y_3}{y_2}=\frac{0.75}{1.5}=0.5$

Function (2) increases exponentially with a common ratio of (0.5) with the increase in x.