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3 years ago

The lengths, in centimeters, of nine earthworms are shown below. 3, 4, 5, 5, 6, 7, 8, 9, 10 What is the median of the data?

Mathematics

1 answer:

mel-nik [20]3 years ago

6 0

The median of the problem is 6 because it is in the middle of the number set of the earthworm sizes.

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What is the radius of a basketball hoop with a circumference of 56.52

evablogger [386]

Answer:

Step-by-step explanation:

R= C/2pi R

56.52/ 2pi=8.99543738355

Answer to 2 significant figures=9.0

7 0

3 years ago

Last year there were 145 pies baked for the bake sale this year k pies baked using k write a expression for the total number of

allsm [11]

Answer:

The number of pies baked in the two years = ( k + 145) pies

Step-by-step explanation:

Here, we are interested in writing an expression for the total number of pies baked in the two years.

Last year, the number of pies baked = 145

This year the number of pies baked = k

Thus, the total number of pies baked in the two years will be ( k + 145) pies

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3 years ago

15x -5 = 45 + 19 what is x

SCORPION-xisa [38]

Answer:

x equals 4.6

Step-by-step explanation:

if u need explanation plz tell me so i can help

4 0

3 years ago

Read 2 more answers

How do I do this?<br>*Look at the directions in the photo*

lora16 [44]

Answer:

$Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2$

Step-by-step explanation:

$We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\$

$As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2$

$For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2$

$For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2$

$Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2$

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2 years ago

| x − 3 | > 7 solve inequality

Cerrena [4.2K]

yuhhh get into ittttttt luv

6 0

3 years ago

Read 2 more answers