Answer:
It’s B
Step-by-step explanation:
I just did it
Answer:
THAT'S CORRECT
Step-by-step explanation:
pls give brainliest
Check the picture below.
so hmmm for the sake of completion, let's check where they intersect
![cos^2(x)sin(x)=sin(x)\implies cos^2(x)sin(x)-sin(x)=0 \\\\\\ sin(x)[cos^2(x)-1]=0\implies \begin{cases} sin(x)=0\\ cos^2(x)-1=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ sin(x)=0\implies x=sin^{-1}(0)\implies \boxed{x=0} \\\\[-0.35em] ~\dotfill\\\\ cos^2(x)-1=0\implies cos^2(x)=1\implies cos(x)=\sqrt{1} \\\\\\ cos(x)=1\implies x=cos^{-1}(1)\implies \boxed{x=\pi}](https://tex.z-dn.net/?f=cos%5E2%28x%29sin%28x%29%3Dsin%28x%29%5Cimplies%20cos%5E2%28x%29sin%28x%29-sin%28x%29%3D0%20%5C%5C%5C%5C%5C%5C%20sin%28x%29%5Bcos%5E2%28x%29-1%5D%3D0%5Cimplies%20%5Cbegin%7Bcases%7D%20sin%28x%29%3D0%5C%5C%20cos%5E2%28x%29-1%3D0%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20sin%28x%29%3D0%5Cimplies%20x%3Dsin%5E%7B-1%7D%280%29%5Cimplies%20%5Cboxed%7Bx%3D0%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20cos%5E2%28x%29-1%3D0%5Cimplies%20cos%5E2%28x%29%3D1%5Cimplies%20cos%28x%29%3D%5Csqrt%7B1%7D%20%5C%5C%5C%5C%5C%5C%20cos%28x%29%3D1%5Cimplies%20x%3Dcos%5E%7B-1%7D%281%29%5Cimplies%20%5Cboxed%7Bx%3D%5Cpi%7D)
now, notice, in the picture the function that is "above" or the "ceiling" function is the sin(x), so we'll get the area under the curve by using "above" - "below" functions.
![\stackrel{above}{sin(x)}~~ - ~~\stackrel{below}{cos^2(x)sin(x)} \implies sin(x)-[1-sin^2(x)]sin(x) \\\\\\ sin(x)-[sin(x)-sin^3(x)]\implies ~~\begin{matrix} sin(x)-sin(x) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ +sin^3(x)\implies sin^3(x)](https://tex.z-dn.net/?f=%5Cstackrel%7Babove%7D%7Bsin%28x%29%7D~~%20-%20~~%5Cstackrel%7Bbelow%7D%7Bcos%5E2%28x%29sin%28x%29%7D%20%5Cimplies%20sin%28x%29-%5B1-sin%5E2%28x%29%5Dsin%28x%29%20%5C%5C%5C%5C%5C%5C%20sin%28x%29-%5Bsin%28x%29-sin%5E3%28x%29%5D%5Cimplies%20~~%5Cbegin%7Bmatrix%7D%20sin%28x%29-sin%28x%29%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%20%2Bsin%5E3%28x%29%5Cimplies%20sin%5E3%28x%29)
now let's use the triple angle identity of sine
![\stackrel{\textit{triple angle identity}}{sin(3x)=3sin(x)-4sin^3(x)}\implies 4sin^3(x)=3sin(x)-sin(3x) \\\\\\ sin^3(x)=\cfrac{3sin(x)-sin(3x)}{4}\implies sin^3(x)=\cfrac{3}{4}sin(x)-\cfrac{1}{4}sin(3x) \\\\[-0.35em] ~\dotfill\\\\ \displaystyle\int\limits_{0}^{\pi }~sin^3(x)dx\implies \int\limits_{0}^{\pi }~\left[ \cfrac{3}{4}sin(x)-\cfrac{1}{4}sin(3x) \right]dx](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Btriple%20angle%20identity%7D%7D%7Bsin%283x%29%3D3sin%28x%29-4sin%5E3%28x%29%7D%5Cimplies%204sin%5E3%28x%29%3D3sin%28x%29-sin%283x%29%20%5C%5C%5C%5C%5C%5C%20sin%5E3%28x%29%3D%5Ccfrac%7B3sin%28x%29-sin%283x%29%7D%7B4%7D%5Cimplies%20sin%5E3%28x%29%3D%5Ccfrac%7B3%7D%7B4%7Dsin%28x%29-%5Ccfrac%7B1%7D%7B4%7Dsin%283x%29%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cdisplaystyle%5Cint%5Climits_%7B0%7D%5E%7B%5Cpi%20%7D~sin%5E3%28x%29dx%5Cimplies%20%5Cint%5Climits_%7B0%7D%5E%7B%5Cpi%20%7D~%5Cleft%5B%20%5Ccfrac%7B3%7D%7B4%7Dsin%28x%29-%5Ccfrac%7B1%7D%7B4%7Dsin%283x%29%20%5Cright%5Ddx)
![\displaystyle \cfrac{3}{4}\int\limits_{0}^{\pi }sin(x)dx-\cfrac{1}{4}\int\limits_{0}^{\pi }sin(3x)dx\implies \left. \cfrac{3}{4} \cdot -cos(x) \right]_{0}^{\pi }-\left. \cfrac{1}{4} \cdot \cfrac{-cos(3x)}{3} \right]_{0}^{\pi } \\\\\\ \cfrac{3}{2}~~ - ~~\cfrac{1}{6}\implies \implies \blacktriangleright \cfrac{4}{3} \blacktriangleleft](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Ccfrac%7B3%7D%7B4%7D%5Cint%5Climits_%7B0%7D%5E%7B%5Cpi%20%7Dsin%28x%29dx-%5Ccfrac%7B1%7D%7B4%7D%5Cint%5Climits_%7B0%7D%5E%7B%5Cpi%20%7Dsin%283x%29dx%5Cimplies%20%5Cleft.%20%5Ccfrac%7B3%7D%7B4%7D%20%5Ccdot%20-cos%28x%29%20%5Cright%5D_%7B0%7D%5E%7B%5Cpi%20%7D-%5Cleft.%20%5Ccfrac%7B1%7D%7B4%7D%20%5Ccdot%20%5Ccfrac%7B-cos%283x%29%7D%7B3%7D%20%5Cright%5D_%7B0%7D%5E%7B%5Cpi%20%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B3%7D%7B2%7D~~%20-%20~~%5Ccfrac%7B1%7D%7B6%7D%5Cimplies%20%5Cimplies%20%5Cblacktriangleright%20%5Ccfrac%7B4%7D%7B3%7D%20%5Cblacktriangleleft)
None of the above
these answers arent equal to the question
So 6 shots equals 25% of the teams total shots(x).
So 6=0.25(x)
x=6/0.25
x=24
If the team made 62.5% of their shots, then they missed 100%-6.25%=37.5%
37.5% of 24= 24(0.375)=9
Hope this helps