Question

Given right triangle SIP such that i = 54 and s = 19, which of the following statements are true? Round to the nearest hundredth.

Answer 1

Hello,

sin S=19/54==>mes S=20.60...° A is false

cos P=19/54==>mes P=69.3993...° B is true
==> C is false


p =√(54²-19²)=50.5470...≈50.55 is true

Answer B AND D

Answer 2

Answer:

 (D)   p = 50.55 (Round to the nearest hundredth).

Step-by-step explanation:

Given: Right triangle SIP such that i = 54 and s = 19.

To find: Which of the following statements are true,  round to the nearest hundredth.

Solution: We have given that Right triangle SIP , i = 54 and s = 19.

By the Pythagoras theorem (IP)²+(SI)² = (SP)².

Plugging the values

                                 (19)²+(p)² = (54)².

                                  361+(p)² =2916

  On subtracting both side by 361.

                     (p)²+ 361 - 361 =2916 -361

                      (p)² = 2555

Taking square root both sides .

                    √(p)² = $\sqrt{2555}$.

                       p = 50.547

p = 50.55 (Round to the nearest hundredth).

Therefore,   (D)   p = 50.55 (Round to the nearest hundredth).