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3 years ago

The faces of a triangular pyramid have a base of 5 cm and height of 11 cm. What is the lateral area of the pyramid?

Mathematics

1 answer:

horrorfan [7]3 years ago

7 0

I think 55 because you would multiply 11×5

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2 years ago

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7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?

loris [4]

Answer: a. Radius of circle = $\sqrt{85}$

b. The equation of this circle : $(x-3)^2+(y-10)^2=85$

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = $\sqrt{(12-3)^2+(12-10)^2}$

Radius of circle = $\sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}$

i.e. Radius of circle = $\sqrt{85}$

b. Equation of a circle = $(x-h)^2+(y-k)^2=r^2$ , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= $\sqrt{85}$ , we get

$(x-3)^2+(y-10)^2=(\sqrt{85})^2$

$(x-3)^2+(y-10)^2=85$

∴ The equation of this circle : $(x-3)^2+(y-10)^2=85$

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3 years ago

Find the sum of 4x^3+2x^2-4x+3 and 7x^3-4x^2+7x+8

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The sum means addition.

Add the like terms together.

4x^3+2x^2-4x+3

+ 7x^3-4x^2+7x+8

4x^3 + 7x^3 = 11x^3

2x^2 + -4x^2 = -2x^2

-4x +7x = 3x

3 +8 = 11

The answer is : 11x^3 - 2x^2 + 3x + 11

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