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3 years ago

What is the equation of the line that passes through the point (5, -6) and has a slope of – 3/5

Mathematics

2 answers:

prohojiy [21]3 years ago

4 0

Answer:

y = -3/5x - 1

Step-by-step explanation:

Slope intercept form is [ y = mx + b ] where m = slope and b = y-intercept.

We know the slope so we need to find the y-intercept.

y = -3/5x + b

-6 = -3/5(5) + b

-6 = -5 + b

-1 = b

y = -3/5x - 1

Best of Luck!

Inessa [10]3 years ago

3 0

Answer:

The answer is

Step-by-step explanation:

To find an equation of a line when given the slope and a point we use the formula

$y - y_1 = m(x - x_1) \\$

where

m is the slope

( x1 , y1) is the point

From the question the point is (5, -6) and slope - 3/5

The equation of the line is

$y + 6 = - \frac{3}{5} (x - 5) \\ y + 6 = - \frac{3}{5} x + 3 \\ y = - \frac{6}{5} x + 3 - 6$

We have the final answer as

$y = - \frac{6}{5} x - 3 \\$

Hope this helps you

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