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timofeeve [1]
3 years ago
11

I deposited $4,000 into an account that earns 5% interest each year. the growth of my investment can be expressed by the exponen

tial equation A= 4000 (1 + 0.5) where is the amount in the account after t years. in how many years will my account exceed $10,000?
Mathematics
1 answer:
natima [27]3 years ago
3 0
We set up the equation 4000*1.05^t>10000.  Dividing by 4000, we seek to find t such that 1.05^5>2.5.  A calculator gives t>18.78, however, since interest is compounded yearly, we want a whole number of years.  The smallest whole number greater than 18.78 is 19.
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What is the slope of the line that passes through the points (-9,1) (3,4)
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Answer:

¼

Step-by-step explanation:

Slope = (y2-y1)/(x2-x1)

= (4-1)/(3-(-9))

= 3/12

= 1/4

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Tim and Tom are trying to earn money to buy a new game system over a 3-month period. Tim saved $45.14 each month. If they need a
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Ayana's chemistry class is exploring how the weight and volume of everyday objects are related. For her first experiment, Ayana
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8 0
3 years ago
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 8x and y = 2x + 2 intersect are the so
son4ous [18]

Answer:

(A)

As per the given condition.

You have 2 equations for y.

i,e y =8x and y= 2x+2

then, they will intersect at some point where y is the same for both equations.

That is why in equation y=8x you exchange y with other equation you got which is y=2x+2 once you do this you will have

8x = 2x+2  and the solution of which will satisfy both equation.

(B)

8x = 2x + 2

to find the solutions take the integer values of x between -3 and 3.

x = -3 , then

8(-3) = 2(-3) +2

-24 = -6+2

-12 = -4    False.

similarly, for x = -2

8(-2) = 2(-2)+2

-16 = -2   False

x = -1

8(-1) = 2(-1)+2

-8= 0   False

x = 0

8(0) = 2(0)+2

0= 2   False

x = 1

8(1) = 2(1)+2

8= 4   False

x = 2

8(2) = 2(2)+2

16 = 6   False

x = 3

8(3) = 2(3)+2

24 = 8   False

there is no solution to 8x = 2x +2 for the integers values of x between -3 and 3.

(C)

The equations cab be solved graphically by plotting the two given functions on a coordinate plane and identifying the point of intersection of the two graphs.

The point of intersection are the values of the variables which satisfy both equations at a particular point.

you can see the graph as shown below , the point of intersection at x =0.333 and value of y = 2.667









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3 years ago
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