Answer:
3544
Step-by-step explanation:
This is a problem of compound growth. The formula is
Where F is the value in the future (in this case, the population after 13 years)
P is the intial amount (here, the initial population of 2000, so P = 2000)
r is the rate of growth (here, it is 4.5%, in decimal, 0.045)
t is the time frame (here, it is 13 years, so t = 13)
<em>we can plug the numbers into the formula and solve for F:</em>
<em>
</em>
<em>rounded to the nearest whole number, the </em><em>population after 13 years would be 3544</em>
As per the given information;
Bacteria triples every month.
Originally, there were 4 bacterial cells.
We are suppose to find how many there will be after 15 months.
Hence we can say , the number of bacteria after n month can be given using the exponential growth function
So number of bacteria after 15 month will be
Answer:
A) 9 and 15.
Step-by-step explanation:
First, let's see what each number's factor is:
A)
9 : 1, 3 & 9
15 : 1, 3, 5 & 15
B)
6 : 1, 2, 3 & 6
10 : 1, 2, 5 & 10
C)
8 : 1, 2, 4 & 8
12 : 1, 2, 3, 4, 6 & 12
Therefore, The number 3 is a common factor of A) 9 and 15.
___
I think it would be FGD and HGD
