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3 years ago

7.003 x 10 to the power of 4

2 answers:

4 0

In scientific notation, just move the decimal point over however many numbers are in the power.

In 7.003 • 10^4, move the decimal point over 4 places to the right, (or left if it's negative) making it 70,030

MAVERICK [17]3 years ago

4 0

Here you need to follow the order of operations.
Parenthesis
Exponents
Multiply
Divide
Add
Subtract
So, following these steps the first thing you would do is multiply 10 to the power of 4 (10^4).
10^4 = 10,000
Next, you would just multiply 7.003 * 10,000
7.003 * 10,000 = 70,030
Hope this helps!

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Which is the completely factored form of 12x3 – 60x2 4x – 20? 4(3x2 – 1)(x – 5) 4x(3x2 1)(x – 5) 4x(3x2 – 1)(x 5) 4(3x2 1)(x – 5

Neporo4naja [7]

The factors of the polynomial are $\rm 4(3x^2 + 1)(x-5)$ .

<h3>Factorization;</h3>

Factorization is nothing but writing a number as the product of smaller numbers.

Given

Polynomial; $\rm 12x^3 - 60x^2 + 4x -20$

To find the factorization the polynomial equates the equation with zero following all the steps given below.

Then,

The factor of the polynomial is;

$\rm 12x^3 - 60x^2 + 4x -20\\\\ 12x^3(x-5)+4(x-5)\\\\(12x^3+4)(x-5)\\\\ 4(3x^2 + 1)(x-5)$

Hence, the factors of the polynomial are $\rm 4(3x^2 + 1)(x-5)$ .

To know more about factorization click the link given below.

brainly.com/question/17595467

4 0

2 years ago

In the equation y = 2(x + 5), if x is increased by 3, then y is increased by

Zielflug [23.3K]

Y is increased by 6 because if you imagine x being 3 then y would = 16 but if you increase x by 3 making 6 then y would = 22 and 16 increased by 6 is 22

8 0

3 years ago

If 3ax+b+c, then x equals?

Viktor [21]

This is not an Equation! this is an Sentence in Al Jebra!
but you means : if 3ax+b=c, then x =?
3ax=c-bX = $x= \frac{c-b}{3a}$

5 0

3 years ago

A small plane took 3 hours to fly 960 km from Ottawa to Halifax with a tail wind. On the return trip, flying into the wind, the

Rina8888 [55]

Answer:

Wind speed: $\rm 40\; km \cdot h^{-1}$ .
Speed of the plane in still air: $\rm 320\; km \cdot h^{-1}$ .

Step-by-step explanation:

This problem involves two unknowns:

wind speed, and
speed of the plane in still air.

Let the speed of the wind be $x \rm \; km \cdot h^{-1}$ , and the speed of the plane in still air be $y\rm \; km \cdot h^{-1}$ . It takes at least two equations to find the exact solutions to a system of two variables.

Information in this question gives two equations:

It takes the plane three hours to travel $\rm 960\; km$ from Ottawa to with a tail wind (that is: at a ground speed of $x + y$ .)
It takes the plane four hours to travel $\rm 960\; km$ from Halifax back to Ottawa while flying into the wind (that is: at a ground speed of $-x + y$ .)

Create a two-by-two system out of these two equations:

$\left\{ \begin{aligned}&3(x + y) = 960 && (1) \\ &4(-x + y) = 960 && (2) \end{aligned}\right.$ .

There can be many ways to solve this system. The approach below avoids multiplying large numbers as much as possible.

Note that this system is equivalent to

$\left\{ \begin{aligned}&4 \times 3 (x + y) = 4\times960 && 4 \times (1) \\ &3\times 4(-x + y) = 3\times 960 && 3 \times (2) \end{aligned}\right.$ .

$\left\{ \begin{aligned}&12 x + 12y = 4\times960 && 4 \times (1) \\ &- 12x + 12y = 3\times 960 && 3 \times (2) \end{aligned}\right.$ .

Either adding or subtracting the two equations will eliminate one of the variables. However, subtracting them gives only $1 \times 960$ on the right-hand side. In comparison, adding them will give $7 \times 960$ , which is much more complex to evaluate. Subtracting the second equation ( $3 \times (2)$ ) from the first ( $4 \times (1)$ ) will give the equation