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3 years ago

Calculate the number of roots of 2sin^3x-5sin^2x+2sinx=0 in the interval 0<=x<=pi

Mathematics

1 answer:

natita [175]3 years ago

6 0

Answer:

Which points are collinear?

G, A, and T

G, E, and T

A, T, and E

G, A, and E

Step-by-step explanation:

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-2+4(-x+4)=10 using distributive property and collecting like terms

stich3 [128]

Answer:

Step-by-step explanation:

$-2+4(-x+4)=10\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\-2+(4)(-x)+(4)(4)=10\\\\-2-4x+16=10\qquad\text{combine like terms}\\\\-4x+(-2+16)=10\\\\-4x+14=10\qquad\text{subtract 14 from both sides}\\\\-4x+14-14=10-14\\\\-4x=-4\qquad\text{divide both sides by (-4)}\\\\\dfrac{-4x}{-4}=\dfrac{-4}{-4}\\\\x=1$

4 0

3 years ago

What is 10r-5r+3r-8r?????

ANEK [815]

Answer:

Step-by-step explanation:

8 0

3 years ago

Find the median: 7, 4, 5, 2, 7, 7, 2. Need answer asap!!

JulsSmile [24]

Answer:

The answer is 5

Step-by-step explanation:

First arrange the numbers in order :

2, 2, 4 ,5, 7, 7, 7

Then find the middle number :

The middle number is 5 , therefore the answer is 5.

7 0

3 years ago

What is the area of the shaded region of the circle?

eduard

Answer:

12π ft², B

Step-by-step explanation:

Area of circle: radius²π

The area of the entire circle would thus be 6²π, or 36π

Note that a circle has a total degree measure of 360°, and the shaded area is 120°. Thus, the area of the shaded region would be 120/360 of the circle's area, or 1/3.

1/3 * total area of the circle = area of the shaded region

1/3 * 36π = 12π

Thus, the answer is 12π ft², or B.

6 0

3 years ago

Plz guys help i need asap<br> its part b im stuck

aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

1st quarter-2
2nd quarter-9
3rd quarter-7
4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

$\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8$

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

$g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4$

Hence, there are 4 more home goals than away goals.

4 0

3 years ago