All categories

3 years ago

4(6c+5) - 2(3c - 5) = 120

Mathematics

2 answers:

ira [324]3 years ago

8 0

Answer:

c=5

Step-by-step explanation:

Simplify both sides of the equation.

4(6c+5)−2(3c−5)=120

(4)(6c)+(4)(5)+(−2)(3c)+(−2)(−5)=120(Distribute)

24c+20+−6c+10=120

(24c+−6c)+(20+10)=120(Combine Like Terms)

18c+30=120

Subtract 30 from both sides.

18c+30−30=120−30

18c=90

Divide both sides by 18.

$\frac{18c}{18}=\frac{90}{18}$

c=5

hope this helps... :/

nlexa [21]3 years ago

7 0

Answer:

$c=5$

Step-by-step explanation:

$4(6c+5)-2(3c-5)=120$

Use the distributive property to expand the equation:

$4(6c)+4(5)-2(3c)-2(-5)=120\\\\24c+20-6c+10=120$

Combine like terms to simplify the equation:

$24c-6c+20+10=120\\\\18c+30=120$

Subtract 30 from both sides:

$18c+30-30=120-30\\\\18c=90$

Isolate the variable c. Divide both sides by 18:

$\frac{18c}{18}=\frac{90}{18}\\\\ c=5$

So, c is equal to 5.

:Done

You might be interested in

(3x+2)∧2=9 how do i solve this in the square root property

Irina18 [472]

$(3x+2)^2=9 \\\\9x^2+12x+4-9=0\\\\9x^2+12x-5=0\\\\a=9,\ \ b=12, \ \ c=-5$

$x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{-12-\sqrt{12^2-4 \cdot9 \cdot (-5)}}{2 \cdot 9}=\frac{-12-\sqrt{144+180}}{18}=\\\\=\frac{-12-\sqrt{324}}{18}=\frac{-12-18}{18}=\frac{-30}{18}=-\frac{5}{3}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-12+\sqrt{12^2-4 \cdot9 \cdot (-5)}}{2 \cdot 9}=\frac{-12+18}{18}=\frac{6}{18}=\frac{1}{3} \\\\Answer: \ x=-\frac{5}{3}\ \ and \ \ x=\frac{1}{3}$

6 0

3 years ago

Given △ABC, use a dilation with the center at the origin to make a similar triangle with side lengths three times as large. What

Artist 52 [7]

The image of the dilation is shown below, with the centre of dilation (0,0) and scale factor of 3

The coordinate of C' is (6, -3) which is three times of the coordinate of C(2, -1)