Question

4(6c+5) - 2(3c - 5) = 120

Answer 1

Answer:

c=5

Step-by-step explanation:

Simplify both sides of the equation.

4(6c+5)−2(3c−5)=120

(4)(6c)+(4)(5)+(−2)(3c)+(−2)(−5)=120(Distribute)

24c+20+−6c+10=120

(24c+−6c)+(20+10)=120(Combine Like Terms)

18c+30=120

Subtract 30 from both sides.

18c+30−30=120−30

18c=90

Divide both sides by 18.

$\frac{18c}{18}=\frac{90}{18}$

c=5

hope this helps... :/

Answer 2

Answer:

$c=5$

Step-by-step explanation:

$4(6c+5)-2(3c-5)=120$

Use the distributive property to expand the equation:

$4(6c)+4(5)-2(3c)-2(-5)=120\\\\24c+20-6c+10=120$

Combine like terms to simplify the equation:

$24c-6c+20+10=120\\\\18c+30=120$

Subtract 30 from both sides:

$18c+30-30=120-30\\\\18c=90$

Isolate the variable c. Divide both sides by 18:

$\frac{18c}{18}=\frac{90}{18}\\\\ c=5$

So, c is equal to 5.

:Done