Answer:
4,099 and 5,011 are the numbers whose ones place is 1/10 the value of the digit in the tens place. Step-by-step explanation: 1 : 4,099 - Yes, The digit at the ones place is 9 and the digit at the tens place is 90 (as per place value). So, 9 is one tenth of 90.
Determine whether each sequence is geometric? <br>
1) 60,48,36,24,12,…<br>
2) 3,6,12,24,48,…
balandron [24]
Answers:
- Not geometric
- Geometric
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Explanation for problem 1
Divide each term over its previous term.
- term2/term1 = 48/60 = 0.8
- term3/term2 = 36/48 = 0.75
We can stop here. The two results 0.8 and 0.75 do not match up, so we don't have a common ratio. Therefore, this sequence is <u>not</u> geometric. A geometric sequence must have each ratio of adjacent terms to be the same value throughout the list of numbers.
Side note: This sequence is arithmetic because we are subtracting the same amount each time (12) to generate each new term.
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Explanation for problem 2
Like before, we'll divide each term by its previous term.
- term2/term1 = 6/3 = 2
- term3/term2 = 12/6 = 2
- term4/term3 = 24/12 = 2
- term5/term4 = 48/24 = 2
Each ratio found was 2. This is the common ratio and it shows we have a geometric sequence. It indicates that each term is twice that of its previous term. Eg: the jump from 12 to 24 is "times 2".
Answer:400
Step-by-step explanation:it didn’t say it gives away and souvenirs so the 6$ can be out the equation and 4000 divided by 10 is 400
Answer:
f[c(p)] = 0.784p
Step-by-step explanation:
sales discount = 30%
sales tax = 12%
c(p) = 0.7p where p is the original price
f(c) = 1.12c where c is the sales price of the bike.
f[c(p)] = 1.12(0.7p)
f[c(p)] = 0.784p Last option.
Assume: p = 100
c(100) = 0.7(100) = 70
f(70) = 1.12(70) = 78.4
f[70(100)] = 0.784(100) = 78.4
Answer:

Step-by-step explanation:
Given that a hyperbola has its centre at (0,0)
Asymptote = y =13x/20
Vertex is on x axis thus a =20
Hence hyperbola will have equation as

Asymptotes would be

Or y=bx/20
Comparing with given equation we get b =13
Hence asymptote would have equation as
