Question

Perform the indicated operation and simplify the result.

Answer 1

$\frac{b^{2}-3b-10 }{(b-2)^{2} }$·$\frac{b-2}{b-5}$=

$\frac{(b-5)(b+2)}{(b-2)^{2} }$·$\frac{b-2}{b-5}$=

$\frac{(b+2)}{(b-2) }$·$\frac{1}{1}$= (semplify)

result = $\frac{(b+2)}{(b-2) }$

Answer 2

Answer : The result is, $\frac{(b+2)}{(b-2)}$

Step-by-step explanation:

The given expression is:

$\frac{b^2-3b-10}{(b-2)^2}\times \frac{(b-2)}{(b-5)}$

First we have to make factors by middle term splitting method.

$\frac{b^2-5b+2b-10}{(b-2)^2}\times \frac{(b-2)}{(b-5)}$

Now we are taking common.

$\frac{b(b-5)+2(b-5)}{(b-2)^2}\times \frac{(b-2)}{(b-5)}$

$\frac{(b-5)(b+2)}{(b-2)^2}\times \frac{(b-2)}{(b-5)}$

By cancelling the terms, we get:

$\frac{(b+2)}{(b-2)}\times \frac{1}{1}$

$\frac{(b+2)}{(b-2)}$

Thus, the result is, $\frac{(b+2)}{(b-2)}$