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serg [7]
3 years ago
7

Perform the indicated operation and simplify the result.

Mathematics
2 answers:
harina [27]3 years ago
6 0

\frac{b^{2}-3b-10 }{(b-2)^{2} }·\frac{b-2}{b-5}=

\frac{(b-5)(b+2)}{(b-2)^{2} }·\frac{b-2}{b-5}=

\frac{(b+2)}{(b-2) }·\frac{1}{1}= (semplify)

result = \frac{(b+2)}{(b-2) }

poizon [28]3 years ago
6 0

Answer : The result is, \frac{(b+2)}{(b-2)}

Step-by-step explanation:

The given expression is:

\frac{b^2-3b-10}{(b-2)^2}\times \frac{(b-2)}{(b-5)}

First we have to make factors by middle term splitting method.

\frac{b^2-5b+2b-10}{(b-2)^2}\times \frac{(b-2)}{(b-5)}

Now we are taking common.

\frac{b(b-5)+2(b-5)}{(b-2)^2}\times \frac{(b-2)}{(b-5)}

\frac{(b-5)(b+2)}{(b-2)^2}\times \frac{(b-2)}{(b-5)}

By cancelling the terms, we get:

\frac{(b+2)}{(b-2)}\times \frac{1}{1}

\frac{(b+2)}{(b-2)}

Thus, the result is, \frac{(b+2)}{(b-2)}

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