|y+4|<1 A) -5 B) -3 C) -4 D) 1 Thank you!!!

A researcher conducts a repeated-measures study to evaluate a treatment with a sample of n = 16 participants and obtains a t sta

Sedaia [141]

Answer:

Option 3) We reject the null hypothesis with one tail test and accept the null hypothesis with two tail test.

Step-by-step explanation:

We are given the following information:

n = 16

$t_{statistic} = 1.94$

$\alpha = 0.05$

Now,

Right One-tail Test

$t_{critical} \text{ at 0.05 level of significance, 15 degree of freedom } = 1.753$

$t_{stat} > t_{critical}$

We reject the null hypothesis in this case.

Two-tail Test

Now, $t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 2.131$

$-2.131 < t_{stat} < 2.131$

We accept the null hypothesis in this case.

Option 3) We reject the null hypothesis with one tail test and accept the null hypothesis with two tail test.

5 0

3 years ago

the depth underwater,d, in meters, of Daisy the dolphin during a dive can be modelled by d=0.1t^2 - 3.5t +6, where t is the time

Dafna1 [17]

Setting d = 0 gives the points where she is at the surface.
therefore 0= 0.1t^2 - 3.5t + 6
apply the quadratic formula to get t = (3.5+- √12.25-4*0.1*6)/0.2
t = (3.5 3.1384709653)/0.2
t= 1.80764517352 and 33.1923548265
subtract the 2 to get the time difference between entry and exit you get
Δt = 31.384709653 seconds

That's as long as I haven't made a mistake :D

4 0

4 years ago

I need an answer ASAP

xeze [42]

It is the 3rd one your welcome

8 0

3 years ago

PLEASE HELP ME T-T I NEED IT’S SOLUTION

Vlada [557]

The area is 8_/3

hope it helps.

6 0

3 years ago

The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th

ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

$|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}$

By doing so, we find:

$|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}$

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

$|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1$

4 0

3 years ago