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Ksivusya [100]
3 years ago
8

Growing sugar beets for sugar, as an alternative to importing sugar made from sugar cane, is an example of

Biology
2 answers:
erastova [34]3 years ago
8 0
Coconut bar. Milly bar.swet items
taurus [48]3 years ago
5 0
Sugar beets for sugar tend to have more minerals and are typically more easy to find than sugar cane so maybe an example of Conservation.
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6 0
3 years ago
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Multiple Allele So far we have studied traits or genes that are coded for by just two alleles. Like in rabbits, there was one al
Vesnalui [34]

Answer:

The correct answer is BB genotype and BO genotype.

Explanation:

The human blood system or ABO system shows codominance due to the multiple alleles. That means three different alleles for human blood type are present are IA, IB, and i. For easy understanding can be stated as A (for IA), B (for IB), and O (for i).

If someone has blood type B could have a genotype of either BB or BO because of the dominance of B allele on O where is If A allele present with B allele it would show co-dominance.

Thus, the correct answer is the BB genotype and BO genotype.

8 0
3 years ago
How many scientific figures in the number 505900
mote1985 [20]
There are <span>scientific (<span>Result: <span>505900</span> or 5.059e+5 (significant figures: 4, decimals: 0)) </span>figures</span> in the number 505900.
5 0
3 years ago
En un cruce entre peces naranjas y peces grises se obtiene una generación (f1) de 50% peces grises . Realice el cruce y explique
Ilya [14]

Answer:

Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).

Explanation:

<u>Datos disponibles:</u>

  • Cruce entre peces naranjas y peces grises
  • 50% de la F1 son peces grises
  • Naranja dominante sobre gris

Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo  para color gris <em>n</em>.

Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.

Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.

Cruce:

Parental)      Nn    x     nn

Gametas)   N    n       n    n

Fenotipos) Naranja     Gris

Cuadro de Punnett)      N           n

                            n       Nn         nn

                            n       Nn         nn

F1)  2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn

     2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,    

     nn

     50% de la progenie será color naranja (Nn)

     50% de la progenie será color gris (nn)

               

3 0
3 years ago
Why is a complex food web better than a simple food chain for the survival of the community?
ziro4ka [17]
Food web provides a better model of an ecosystem and model of many different consumers
5 0
3 years ago
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