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Diano4ka-milaya [45]

3 years ago

11

What is -1/p^-6 ???

1 answer:

wariber [46]3 years ago

4 0

$- \frac{1}{ {p}^{ - 6} } = - \frac{1}{ \frac{1}{ {p}^{6} } } = - {p}^{6}$

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The estimate obtained from a sample of which of the following sizes would most likely be closest to the actual parameter value o

SOVA2 [1]

To obtain an estimate of a parameter of a population, we use confidence intervals.

Confidence intervals:

The larger the sample size, the closest the parameter estimate is to the value of the population, as the margin of error of confidence intervals is inversely proportional to the sample size, that is, a greater sample leads to a smaller margin of error.

Thus, you should select the highest sample size in the options.

For more on confidence interval/margin of error, you can check brainly.com/question/22718960

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3 years ago

Superman needs to save Lois from the clutches of Lex Luthor. After flying for 5 seconds, he is 1845 meters from her. Then at 15

Lapatulllka [165]

Answer:

do not know what the question is but the equation for this would be

y=2100-51x

7 0

3 years ago

Read 2 more answers

How do you write the equation 0=x+1 in standard form

Elanso [62]

Answer:

x=-1

Step-by-step explanation:

7 0

3 years ago

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Please I really need help 100 points

Afina-wow [57]

Multiply the first equation by 3 and the second equation by 2:

$\begin{cases}6x-9y=27\\6x+10y=8\end{cases}$

Subtract the two equation to get rid of the x variable:

$-9y-10y=27-8 \iff -19y = 19 \iff y = -1$

Use the value of y to determine the value of x: for example, using the first equation we have

$2x+3=9 \iff 2x=6 \iff x=3$

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3 years ago

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The term "freshman 15" refers to the claim that college students typically gain 15lbs during freshman year at college. Assume th

Viefleur [7K]

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

<h3>What is Probability ?</h3>

Probability is defined as the likeliness of an event to happen.

Let X be a random variable that shows the term "freshman 15" that claims that students typically gain 15lb during their freshman year at college.

It is given that

X follows is a normal distribution with a mean of 2.1 lb (μ) and a standard deviation (σ) of 10.8 lb.

Population Mean (μ) = 2.1

Population Standard Deviation (σ) = 10.8

We need to compute Pr(X≥15). The corresponding z-value needed to be computed is:

$\rm Z_{lower} = \dfrac{ X_1 -\mu }{\sigma}\\\\Z_{lower} = \dfrac{ 15-2.1 }{10.8}\\\\\\Z_{lower} = 1.19$

Then the probability is given as

$\rm Pr(X \geq 16 ) = Pr (\dfrac{X -21}{10.8} \geq \dfrac{15-21}{10.8})\\\\= Pr (Z \geq \dfrac{15-2.1}{10.8}\\\\= Pr (Z\geq 1.19)\\\\ = 0.1162$

Pr(X≥15)=0.1162. (11.6%)

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

To know more about Probability

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3 0

2 years ago