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SVEN [57.7K]
3 years ago
12

A salesman must commute 1 hour and 48 minutes from his house to the airport, fly to another city and take a bus to his destinati

on. What is the total travel time one way? Distance between 2 airports = 1,980 miles. Average speed of airplane = 550 mph. Travel time by bus after arrival at airport = 30 minutes.
Mathematics
2 answers:
irina [24]3 years ago
4 0
5 hours and 54 minutes.
Veseljchak [2.6K]3 years ago
4 0

Time spent on the airplane:

Time = Distance ÷ speed = 1980/550 = 3.6 hours = 3 h 36 mins


Total time needed = 1 h 48 mins + 3 h 36 mins + 30 mins = 4 h 114 mins


4 h 114 min = <u>5h 54 mins</u>


Answer: Total travel time = 5h 54 mins


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Step-by-step explanation:

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4 years ago
How can the techniques of factoring be extended to work with higher-degree polynomials?
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<h3>Explanation:</h3>

Any techniques that you're familiar with can be applied to polynomials of any degree. These might include ...

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3 years ago
In a quadrilateral ABCD, angle A + angle D = 90°. Prove that AC^2 + BD^2 = BC^2 + AD^2​
olga2289 [7]

Answer:

AD^{2}+BC^{2}=AE^{2}+ED^{2}+BE^{2}+EC^{2}

AC^{2}+BD^{2}=AE^{2}+EC^{2}+BE^{2}+ED^{2}

Hence prove.

AC^{2}+BD^{2}=BC^{2}+AD^{2}

Step-by-step explanation:

Given:

∠A + ∠D = 90°

We are prove to that

AC^{2}+BD^{2}=BC^{2}+AD^{2}

Solution:

See required figure in attached file.

We know sum of the all angles of a triangle is 180°.

So, in triangle AED.

∠A + ∠E + ∠D = 180°

∠E + (∠A + ∠D) = 180°

Now, we substitute ∠A + ∠D = 90° in above equation.

∠E + 90° = 180°

∠E = 180° - 90°

∠E = 90°

Using Pythagoras Theorem for triangle ADE and triangle BEC.

AD^{2}=AE^{2}+ED^{2}

BC^{2}=BE^{2}+EC^{2}

Now, we add both above equations.

AD^{2}+BC^{2}=AE^{2}+ED^{2}+BE^{2}+EC^{2}--------(1)

Similarly, Using Pythagoras Theorem for triangle AEC and triangle BED.

AC^{2}=AE^{2}+EC^{2}

BD^{2}=BE^{2}+ED^{2}

Now, we add both above equations.

AC^{2}+BD^{2}=AE^{2}+EC^{2}+BE^{2}+ED^{2}--------(2)

We get From equation 1 and equation 2.

AC^{2}+BD^{2}=BC^{2}+AD^{2}

Hence prove,

AC^{2}+BD^{2}=BC^{2}+AD^{2}

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Answer:

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Step-by-step explanation:

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