Question

6(2x²-5) = [?] x = -3

Answer 1

Answer:

78

Step-by-step explanation:

plug in -3 as x

6(2(-3)^2-5)

6(2(9)-5)

6(18-5)

6(13)

78

Answer 2

Answer: 78

Step-by-Step Solution:

=> 6(2x² - 5) ; when x = -3

Substitute the value of ‘x’ :-

= 6(2x² - 5)
= 6(2(-3)² - 5)
= 6(2(9) - 5)
= 6(18 - 5)
= 6(13)
= 6 * 13
=> 78