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Delicious77 [7]
3 years ago
5

Directions: Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about t

he amounts of potential and kinetic energy the bowling ball has:
• as sits on top of a building that is 40 meters tall.
• as it is half way through a fall off a building that is 40 meters tall and travelling 19.8 meters per second.
• as it is just about to hit the ground from a fall off a building that is 40 meters tall and travelling 28 meters per second.

1. Does the bowling ball have more potential energy or kinetic energy as it sit on top of the building? Why?
Chemistry
1 answer:
Leto [7]3 years ago
6 0

Answer:

Potential

Explanation:

The higher the elevation is the higher the potential energy levels are also the ball is not moving so it is not using kinetic energy.

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Which of the following trends can be identified on the periodic table?
Jet001 [13]

Answer:

D) atomic radii increase from top to bottom of a group

Explanation:

Atomic radii trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

Other options are incorrect because,

A) atomic radii increase from left to right across the period

Correct = atomic radii decreases from left to right across the period

B) ionization energy increases from top to bottom within a family

Correct =  ionization energy decreases from top to bottom within a family

C) electronegativity decreases from left to right across a period

Correct = electronegativity increases from left to right across a period

8 0
4 years ago
A car can accelerate from a standstill to 100 km/h [E] in 9.60s. calculate the average acceleration
Lelu [443]

Answer:

Acceleration is :

a = 2.89 m/s2

Explanation:

Acceleration : It is the change in the velocity of the object per unit time.

The object starts from the rest , so the initial velocity of the object is zero.

Initial velocity , u = 0

Final velocity = 100 km/h

Change the velocity to m/s because[ time unit is in second(9.60 s)]

1 km = 1000 m

1 hour = 60 x 60 sec = 3600 sec

1km/h=\frac{1000}{3600}m/s

1km/hr=\frac{5}{18}

100km/hr=\frac{5}{18}\times 100

v=\frac{5}{18}\times 100

v = 27.78 m/s

u = 0 m/s

time = 9.60 s

The acceleration"a" is calculated using :

a=\frac{v-u}{t}

a=\frac{27.78-0}{9.6}

a=\frac{27.78}{9.6}

a=2.89m/s^{2}

5 0
3 years ago
Mixing solutions of sodium hydroxide and rubidium nitrate will cause rubidium hydroxide to precipitate. You have a 1.50 mol/L so
Crazy boy [7]

Answer:

97.6 mL of Sodium Hydroxide and 732 mL of Rubidium Nitrate are needed to make 15 g of Rubidium hydroxide.

Explanation:

The chemical reaction described in the question can be given as

NaOH + RbNO₃ → RbOH + NaNO₃

We want to find the amount of each reactant that reacted to give 15 g of RbOH

Amount of RbOH produced from the reaction = 15 g,

We first convert to number of moles, to be able to obtain the number of moles of each reactant from the stoichiometric balance of the reaction.

Number of moles = (Mass)/(Molar Mass)

Molar Mass of RbOH = 102.475 g/mol

Number of moles of RbOH produced from the reaction = (15/102.475) = 0.1464 moles.

Note that from the stoichiometric balance of the reaction,

1 mole of RbOH was produced from 1 mole of RbNO₃

And

1 mole of RbOH was produced from 1 mole of NaOH.

So,

0.1464 mole of RbOH will be produced from 0.1464 mole of RbNO₃

And

0.1464 mole of RbOH will be produced from 0.1464 mole of NaOH

Note that,

Number of moles = (Concentration in mol/L) × (Volume in L)

For RbNO₃,

Number of moles = 0.1464 mole

Concentration in mol/L = 0.200 mol/L

Volume in L = ?

0.1464 = 0.2 × (Volume in L)

Volume in L = (0.1464/0.20) = 0.732 L = 732 mL

For NaOH,

Number of moles = 0.1464 mole

Concentration in mol/L = 1.50 mol/L

Volume in L = ?

0.1464 = 1.50 × (Volume in L)

Volume in L = (0.1464/1.50) = 0.0976 L = 97.6 mL

Hope this Helps!!!

4 0
3 years ago
The specific heats and densities of several materials are given below: Material Specific Heat (cal/g·°C) Density (g/cm3) Brick 0
abruzzese [7]

<u>Answer:</u> The change in temperature is 84.7°C

<u>Explanation:</u>

To calculate the change in temperature, we use the equation:

q=mc\Delta T

where,

q = heat absorbed = 1 kCal = 1000 Cal    (Conversion factor: 1 kCal = 1000 Cal)

m = mass of steel = 100 g

c = specific heat capacity of steel = 0.118 Cal/g.°C

\Delta T = change in temperature = ?

Putting values in above equation, we get:

1000cal=100g\times 0.118cal/g^oC\times \Delta T\\\\\Delta T=\frac{1000cal}{100g\times 0.118cal/g^oC}\\\\\Delta T=84.7^oC

Hence, the change in temperature is 84.7°C

5 0
3 years ago
How many times greater is the rate of effusion of oxygen gas than that of carbon dioxide
elena55 [62]

1.173

hope u get 100%!!

7 0
3 years ago
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