Which best explains why water dissolves most salts?

What is the molarity of HCl if 34.81 mL of a solution of HCl contain 0.3297 g of HCl?

Temka [501]

Answer:

0.2598 M

Explanation:

Molarity is mol/L, so we have to convert the grams to moles and the mL to L. To convert between grams and moles you need the molar mass of the compound, which is 36.46g/mol.

$0.3297gHCl*\frac{1molHCl}{36.46gHCL} = 0.00904279 mol HCl$

$34.81 mLHCl * \frac{1L}{1000L} = 0.03481 L HCl$

$\frac{0.00904279molHCl}{0.03481 L HCl} = 0.25977554 mol/L$

Round to the lowest number of significant figures = 0.2598 M

6 0

3 years ago

Analysis of a compound of sulfur, oxygen and fluorine showed that it is 31.42% S and 31.35% O, with F accounting for the remaind

Leya [2.2K]

Answer:

The molecular formula is SO2F2

Explanation:

Step 1: Data given

Suppose the mass of compound = 100 grams

The compound contains:

31.42 % S = 31.42 grams S

31.35 % O = 31.35 grams O

100 - 31.42 - 31.35 = 37.23 F

Molar mass of S = 32.065 g/mol

Molar mass F = 19.00 g/mol

Molar mass O = 16.00 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles S = 31.42 grams / 32.065 g/mol

Moles S = 0.9799 moles

Moles 0 = 31.35 grams / 16.00 g/mol

Moles 0 = 1.959 moles

Moles F = 37.23 grams / 19.00 g/mol

Moles F = 1.959 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

S: 0.9799 / 0.9799 = 1

F: 1.959/ 0.9799 = 2

O : 1.959 / 0.9799 = 2

The empirical formula is SO2F2

This formula has a molecular mass of 102.06 g/mol

This means the empirical formula is also the molecular formula : SO2F2

3 0

2 years ago

The survival of aquatic organisms depends on the small amount of O2 that dissolves in H2O . The diagrams above represent possibl

koban [17]

Answer:

Diagram 1

Explanation:

The solubility of the oxygen gas in water has to do with the interaction of the oxygen with the dipoles in water.

Water is a polar molecule having oxygen as the negative dipole and hydrogen as the positive dipole.

Water can interact with the oxygen atoms in the molecule via intermolecular hydrogen bonds with molecular oxygen as shown in diagram 1.

4 0

2 years ago

7. Write a formula for each of the following:

sergeinik [125]

Answer : The formula for each of the following is:

(a) $C_{22}H_{46}$

(b) $C_{17}H_{34}$

(c) $C_{13}H_{24}$

Explanation :

Alkanes are hydrocarbon in which the carbon atoms are connected with single covalent bonds.

The general formula of alkanes is $C_n H_{2n+2}$ where n is the number of the carbon atoms present in a molecule of alkane.

Alkenes are hydrocarbon in which the carbon atoms are connected with double covalent bonds.

The general formula of alkenes is $C_n H_{2n}$ where n is the number of the carbon atoms present in a molecule of alkene.

Alkynes are hydrocarbon in which the carbon atoms are connected with triple covalent bonds.

The general formula of alkynes is $C_n H_{2n-2}$ where n is the number of the carbon atoms present in a molecule of alkyne.

(a) An alkane with 22 carbon atoms

Putting n = 22 in the general formula of alkane, we get the formula of alkane as, $C_{22}H_{2(22)+2}$ or $C_{22}H_{46}$

(b) An alkene with 17 carbon atoms

Putting n = 17 in the general formula of alkene, we get the formula of alkene as, $C_{17}H_{2(17)}$ or $C_{17}H_{34}$

(c) An alkyne with 13 carbon atoms

Putting n = 13 in the general formula of alkyne, we get the formula of alkyne as, $C_{13}H_{2(13)-2}$ or $C_{13}H_{24}$

3 0

3 years ago

Read 2 more answers

Write a balanced chemical equation (smallest integer coefficients possible) for the reaction between an acid and a base that lea

11Alexandr11 [23.1K]

Answer:

2HClO4(aq) + Ca(OH)2(aq) → Ca(ClO4)2(aq) + 2H2O(l)

Perchloric acid + Calcium hydroxide → Calcium perchlorate + Water.

Explanation:

This is a neutralization reaction where the acid, Perchloric acid reacts completely with an appropriate amount of base, aqueous Calcium hydroxide to produce salt, aqueous Calcium perchlorate and water, liquid H2O only.

During this reaction, the hydrogen ion, H+, from the HClO4 is neutralized by the hydroxide ion, OH-, from the Ca(OH)2 to form the water molecule, H2O.

Thus, it is called a neutralization reaction.

6 0

3 years ago