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s2008m [1.1K]
4 years ago
15

(4a−a3−3)+(2a3−5a2+8) find the sum

Mathematics
1 answer:
NikAS [45]4 years ago
7 0

Answer: a3−5a2+4a+5

Step-by-step explanation:

4a+−a3+−3+2a3+−5a2+8

=(−a3+2a3)+(−5a2)+(4a)+(−3+8)

=a3+−5a2+4a+5

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Write a equation in standard form that represents the points (1, -4) and (3,-5) Answer for
serious [3.7K]

Answer:

Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.

9x+3y = 36

3y= - 9x + 36

y = -3x + 12

The slope, m = -3

------------------

The slope of lines parallel is the same.

The slope of lines perpendicular is the negative inverse, m = +1/3

----------------

Use y = mx + b and the point (1,2) to find b.

2 = (1/3)*1 + b

b = 5/3

The equation is y = (1/3)x + 5/3 (slope-intercept form)

x - 3y = -5 (standard form)

Step-by-step explanation:please give me brainliest

6 0
3 years ago
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The following figure is made of a triangle and a rectangle. All of the sides of the triangle are the same length.
Andru [333]

Answer:

130cm

Step-by-step explanation:

the perimeter of the triangle is 15 the perimeter of the rectangle is 150 + 115 + 15 equals 103 ♥ hope it helped

7 0
3 years ago
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what is an equation of the line that passes through the point (-1,4) and is perpendicular to the line x-6y=12
Alecsey [184]

Answer:

6x + y = 3

Step-by-step explanation:

The product of two lines that are perpendicular to each other is -1

If line A has a slope of m1

and line B has a slope of m2 and they are perpendicular to each other,

then the product of the two lines is

m1 X m2 = -1

We are given two lines that are perpendicular to each other in the question.

The first line has the equation

x - 6y =12

We can write the slope form of the equation y = mx + c

m = slope

x - 6y = 12

Make y subject of formula

6y = x - 12

y = x/6 - 12/6

y = x/6 - 2

y =(1/6)x - 2

Comparing y=mx+c and y=(1/6)x-2,

m corresponds to 1/6

Therefore, we can say that the slope, m of the line x-6y=12

is 1/6

Recall, for two lines that are perpendicular to each other,

m1 X m2 = -1

m1 = 1/6

1/6 X m2 = -1

m2/6 = -1

Cross multiply

m2 = 6 X -1

m2 = -6

Step 3

To find the equation of the second line with slope, m2 = -6 and that passes through the point (-1,4)

Points are represented by coordinates (x, y)

the slope of a line is given by

m = (y - y1)/(x-x1)

Given in the question, the point (-1,4) corresponds to (x1, y1).

As calculated earlier, the slope of the second line is -6

-6 = (y - 4)/[x - (-1)]

-6 = (y - 4)/(x + 1)

Cross multiply

y - 4 = -6(x + 1)

y - 4 = -6x - 1

y = -6x - 1 + 4

y = -6x + 3

this equation is the slope form equation of the line

6x + y = 3 is the general form of the equation

4 0
4 years ago
X - 12/2 = 20<br> hurry pls!!!
Westkost [7]

Answer:

26

Step-by-step explanation:

12/2=6

x-6=20

x-6+6=20+6

=26

7 0
3 years ago
What is an equation of the line that passes through the point (-5,-3)(−5,−3) and is parallel to the line 3x+5y=15
Sunny_sXe [5.5K]

Answer:

  • y = -3/5x - 6 or 3x + 5y = -30

Step-by-step explanation:

<u>Given line:</u>

  • 3x + 5y = 15

<u>Converting into slope-intercept form:</u>

  • 3x + 5y = 15
  • 5y = - 3x + 15
  • y = -3/5x + 3

<u>Parallel lines have the same slope, so the parallel line will be:</u>

  • y = -3/5x + b

<u>Using given point (-5, -3) finding the y-intercept:</u>

  • -3 = -3/5(-5) + b
  • -3 = 3 + b
  • b = -3 - 3
  • b = -6

<u>So the line is:</u>

  • y = -3/5x - 6

<u>Or converted into standard form:</u>

  • y = - 3/5x - 6
  • 3/5x + y = -6
  • 3x + 5y = -30
8 0
3 years ago
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