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NikAS [45]
3 years ago
11

The measures of two angles have a a sum of 180°. The measures if the angles are in a ratio of 5:1. Determine the measures of bot

h angles by setting up and solving an equation.

Mathematics
1 answer:
Tasya [4]3 years ago
4 0

Answer:

one angle is 150 degrees and the other is 30 degrees.

Step-by-step explanation:

please kindly check the attached file for explanation.

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What degree of rotation is represented on this matrix
Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, -90^{\circ}

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}

Given the matrix: \begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}

Now, equate the given matrix with standard matrix we have;

\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix} =  \begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}

On comparing we get;

\cos \theta = 0       and -\sin \theta =1  

As,we know:

  • \cos \theta = \cos(-\theta)
  • \sin(-\theta) = -\sin \theta

\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})

we get;

\theta = -90^{\circ}

and

\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})

we get;

\theta = -90^{\circ}

Therefore, the degree of rotation is, -90^{\circ}

7 0
3 years ago
How many sevens are there is 3500
Marrrta [24]

Answer:

there are no seven in there

7 0
3 years ago
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What is the missing base for 1/9=(__) to the second power
Arisa [49]
1/3
<( ̄︶ ̄)> []~( ̄▽ ̄)~* ( ̄﹏ ̄) ( ̄ˇ ̄)
5 0
3 years ago
Determine the coordinates of the intersection of the diagonals of square ABCD with verticals A(-4,6), B(5,6) C(4,-2), and D(-5,-
timama [110]

Given:

Vertices of a square are A(-4,6), B(5,6) C(4,-2), and D(-5,-2).

To find:

The intersection of the diagonals of square ABCD.

Solution:

We know that diagonals of a square always bisect each other. It means intersection of the diagonals of square is the midpoint of diagonals.

In the square ABCD, AC and BD are two diagonals. So, intersection of the diagonals is the midpoint of both AC and BD.

We can find midpoint of either AC or BD because both will result the same.

Midpoint of A(-4,6) and C(4,-2) is

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Midpoint=\left(\dfrac{-4+4}{2},\dfrac{6+(-2)}{2}\right)

Midpoint=\left(\dfrac{0}{2},\dfrac{6-2}{2}\right)

Midpoint=\left(\dfrac{0}{2},\dfrac{4}{2}\right)

Midpoint=\left(0,2\right)

Therefore, the intersection of the diagonals of square ABCD is (0,2).

4 0
3 years ago
HERE a question........
Pani-rosa [81]

Answer:

6

Step-by-step explanation:

Split the shape into two shapes, one square and one triangle.

Find the area of the square and area of triangle.

area of square = 2 × 2 = 4

The height of the triangle is 4 - 2 = 2 units.

area of triangle = 2 × 2 × 1/2 = 2

Add the areas.

4 + 2 = 6

The area is 6 units².

4 0
3 years ago
Read 2 more answers
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