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2 years ago

10

The circle graph shows the results of a survey in which 250 students were asked to choose their favorite color. How many more st

udents chose purple than red as their favorite color?

1 answer:

Alex Ar [27]2 years ago

6 0

Answer:

The correct answer is 4%

Step-by-step explanation:

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Relay races called for 8 people on a team. There were 43 men and 34 women who wanted to race. How many teams could be formed ?ho

ELEN [110]

It would be an odd number of teams. What I did was add 43 and 34 together. Which gave me 77. So 77 people total wanted to race. There can only be 8 racers on each team. Each means to divide. So I divided 8 and 77. It gave me 9 with a remainder of 5. So there will e 9 teams and 5 racers left out. (:

4 0

2 years ago

Sam built a fence that was 54 feet long she built the same legnth of fence each day for 6 days how many inches of fence did Sam

FromTheMoon [43]

Answer:

9 inches a day

Step-by-step explanation:

9 multiplied by 6 is 54

4 0

2 years ago

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I need help I’m stuck on this

arsen [322]

press ask for help i think it my help im also stumped on that

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2 years ago

The gym teacher has $250 to spend on volleyball equipment. She buys 4 volleyball nets for $28 each. Volleyballs cost $7 each. Ho

pav-90 [236]

Answer:

The maximum number of volleyballs that she can buy is 19

Step-by-step explanation:

Let

x ----> the number of volleyballs

we know that

The cost of each volleyball net ($28) by the number of volleyball nets (4) plus the cost of each volleyball ($7) multiplied by the number of volleyballs (x) must be less than or equal to $250

so

The inequality that represent this situation is

$28(4)+7x\leq 250$

Solve for x

$112+7x\leq 250$

subtract 112 both sides

$7x\leq 250-112$

$7x\leq 138$

Divide by 7 both sides

$x\leq 19.7$

therefore

The maximum number of volleyballs that she can buy is 19

4 0

3 years ago

The logarithmic expression ln(√e/y^3) can be rewritten as

kvv77 [185]

Answer:

$\dfrac{1 - 6 \ln y}{2}$

Step-by-step explanation:

$\ln \dfrac{\sqrt{e}}{y^3} =$

$= \ln \dfrac{e^\frac{1}{2}}{y^3}$

$= \ln e^\frac{1}{2} - \ln y^3$

$= \dfrac{1}{2} \ln e - 3 \ln y$

$= \dfrac{1}{2} - 3 \ln y$

$= \dfrac{1 - 6 \ln y}{2}$

6 0

2 years ago