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vredina [299]
3 years ago
13

Each edge of a cube measures 12.1 in. What is the surface area of the cube?

Mathematics
1 answer:
REY [17]3 years ago
8 0
878.46 in. is your answer! Hope this helps!
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Choose all lengths that are equal to<br> 6 feet 12 inches.
Mumz [18]

Answer:

Can you show a picture? Or like tell us the options?

7 0
3 years ago
The circumference of a circle is 25.12cm. What is the area of the circle? Use 3.14
malfutka [58]
C=2pir
area=pir^2

given
c=25.12
25.12=2pir
pi=3.14
25.12=2(3.14)r
25.12=6.28r
divide both sides by 6.25
4=r

sub into other
area=pir^2
area=pi4^2
area=16pi
area=16(3.14)
area=50.24

the area is 50.24 square cm
3 0
3 years ago
A girl makes 515 per hour as a math tutor. Her paycheck is calculated by multiplying $15 times the number of hours she worked. H
goldenfox [79]

Answer:     373.33 Hours

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h
Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

4 0
3 years ago
(b)The sum of n terms of a certain series is 3n² + 10n for all values
Angelina_Jolie [31]

Step-by-step explanation:

The nth term just mean how to work out the next number in he series. In this series of numbers, you have to square three n and add it onto 10 n to do this.

N is the term- the number it comes in the sequence.

Example:

2 3 4 5 6

2= the first terof the sequence

3= second term

4=3rd term

And so on

To work out what the next term is (6th term) you use this expression:

N+1

The first term is 2. As it is the first n=1. 1+1=2 so that works

The seco d term is 3. As it is the second term n=2. 2+1+3 so that works

And so on

This might help

But you have to do the rest

5 0
3 years ago
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