All categories

3 years ago

Use long division to find the quotient below. (x2 + x – 20) ÷ (x – 4)

Mathematics

1 answer:

marta [7]3 years ago

8 0

Answer:

( x2 + x - 20 ) ÷ ( x - 4 ) = x + 5

Hope this helps,

Davinia.

You might be interested in

Which equation shown below represents the equation of the inverse of the quadratic function shown below?

algol13

Is (x-2)/3 -3 a choice?

6 0

3 years ago

Read 2 more answers

Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC =16 and DC=5 what is the length of BC in the simplest ra

Nana76 [90]

The length of BC is $4 \sqrt{5}$ .

Solution:

Given ABC is a right triangle.

AC is the hypotenuse and BD is the altitude.

AB and BC are legs of the triangle ABC.

AC = 16 and DC = 5

<u>Leg rule of geometric mean theorem:</u>

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

$\Rightarrow \frac{AC}{BC}=\frac{BC}{DC}$

$\Rightarrow \frac{16}{x}=\frac{x}{5}$

Do cross multiplication.

$\Rightarrow 16\times 5 = x\times x$

$\Rightarrow 80= x^2$

$\Rightarrow 16\times 5= x^2$

Taking square root on both sides.

$\Rightarrow \sqrt{16\times 5} = \sqrt{x^2}$

$\Rightarrow \sqrt{4^2\times 5} = \sqrt{x^2}$

square and square roots get canceled, we get

$\Rightarrow 4\sqrt{ 5} = x$

The length of BC is $4 \sqrt{5}$ .

7 0

3 years ago

4x when x = 3/4 (I really need help)

hoa [83]

3/4 is 0.75 as a decimal so 4 x 0.75 = 3

8 0

3 years ago

The length of a rectangular garden is 7 feet longer than its width. The perimeter of the garden is 38 feet. Find the width and l

Blizzard [7]

38=2(2w+7)
19=2w+7
12=2w

w=6
l=13

5 0

3 years ago

The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length.

emmasim [6.3K]

Step-by-step explanation:

1) The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length....

= Solution ,

Length ( L ) = ?

breadth ( b ) = 10xy cm

area ( a ) = ( 30x² + 20xy )

Now ,

area ( a ) = l × b

or, ( 30x²y + 20xy ) = L × 10xy cm

$or,\frac{30 {xy + 20xy}^{2} }{10xy} = l \\$

$or, \: l = 3 {x}^{2 - 1} + 2cm$

$\boxed{\sf{l = (3x+2)cm}}$

2) Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.

= Solution,

$= \frac{20 {x}^{4} {y}^{2} }{5 {x}^{3} y} \\$

$= 4xy$

The product of 3x and 4y = 6xy

= 6x - 4xy

$= \boxed{\sf {2xy}}$

hope it helped !!!!

7 0

2 years ago