Carson needed pencil and erasers, but the total amount can not be over 40. Pencils were $4 and erasers were 5$. How much pencils and erasers can he buy without spender over $80
Answer:
(using substitution to solve the problem)
x=y-3
2x+y=12
2(y-3)+y=12
2y-6+y=12
3y=18
y=6
y=6
x=6-3
= (3, 6)
Step-by-step explanation:
using substitution, substitute the x in the second equation to y-3, to find the value of y. after that distribute the 2 into the parenthesis and collect like terms. once you simplify, you have the value of y, so substitute the value of y into the first equation to find x. once you have both values put them in the ordered pair form and you're done.
i hope this helps :)
I just took the test and the correct answer that i got was B
You need to attach a picture or something
Answer:
a) 10
b) The $40+5 dollars for every ticket
c) See below
Step-by-step explanation:
a)
1. Let t=number of tickets
2. Writing an equation
Breaking even means that you earn the same amount of money for both.
40 +5t=70+2t
3. Solving the equation
40 +5t=70+2t
5t-2t=70-40
3t=30
t=10
So the answer to a) is 10.
b)
1. Using an equation
We already know that there are 2 equations for this problem. (40+5t, 70+2t)
So, we will substitute 20 for t.
40+5*20=40+100=140
70+2t=70+2*20=110
2. Comparing equations
140>110, so the first offer is better
C)
The owner lets you choose how you get paid because one option will be better for you, as some days you might not sell many tickets (so you will go with the $70+2 tickets), or some days you might sell many tickets (you will choose the $40+5 dollars/ticket).
