Given that <span>For
a certain model of car the distance

required to stop the vehicle if
it is traveling at

mi/h is given by the formula
![d=v+\frac{v^2}{20}, where [tex]d](https://tex.z-dn.net/?f=d%3Dv%2B%5Cfrac%7Bv%5E2%7D%7B20%7D%2C%20where%20%5Btex%5Dd%20)
is measured in feet.
If Kerry wants her stopping distance not to exceed 75
ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

Therefore, the range of speed she can travel is

</span>
In this equation, you have to treat the number in the bracket first on the basis of BODMAS
15 - [-3]- 4
Note that when two minuses come together the product is a plus sign.
15 +3 - 4
You have to add before you subract
18 - 4 =14
Therefore, 15- [-3] - 4 = 14.
Answer:I think the answer is letter B.
Step-by-step explanation:
Answer:
One solution
Step-by-step explanation:
0.75 (x + 40) = 0.35 (x + 20) + 0.35 (x + 20)
0.75x + 30 = 0.35x + 7 + 0.35x + 7
0.75x + 30 = 0.7x + 14
0.05x + 30 = 14
0.05x = -16
x = -320
Hope this helps!
In this item, I assume that the variable "e" here stands for the Euler number which is equal to 2.718. Raising this number to the exponent -2.8 will give us an answer of,
y = e^-2.8 = (2.718)^-2.8 = 0.0608
Therefore, the value of y is approximately 0.1.