Answer:
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
Step-by-step explanation:
We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.
Firstly, Let X = women's gestation period
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= average gestation period = 270 days
= standard deviation = 9 days
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X
261)
P(X < 279) = P(
<
) = P(Z < 1) = 0.84134
P(X
261) = P(
) = P(Z
-1) = 1 - P(Z < 1)
= 1 - 0.84134 = 0.15866
<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>
Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
Answer:
8
Step-by-step explanation:
Hope it helps
:D
Can i have brainly pls
Answer:
It is B. (0,1)
Step-by-step explanation:
Answer:
4.718592
Step-by-step explanation:
To get to -14.4 from 18 you multiply 18 x 0.8
Repeat that until you get to the 7th term
18 (1st)
18 x 0.8 = -14.4 (2nd)
-14.4 x 0.8 = 11.52 (3rd)
11.52 x 0.8 = 9.216 (4th)
9.216 x 0.8 = 7.3728 (5th)
7.3728 x 0.8 = 5.89824 (6th)
5.89824 x 0.8 = 4.718592 (7th)