<h3>
Answer: E) 8i</h3>
Explanation:
By definition, i = sqrt(-1)
Which means,
sqrt(-64) = sqrt(-1*64)
sqrt(-64) = sqrt(-1)*sqrt(64)
sqrt(-64) = i*sqrt(8^2)
sqrt(-64) = i*8
sqrt(-64) = 8i
On the second line, I used the rule sqrt(x*y) = sqrt(x)*sqrt(y). The fourth line used the rule sqrt(x^2) = x when x is nonnegative.
Answer:
<u>384 cm²</u>
Step-by-step explanation:
Property of rhombus :
- Diagonals of rhombus bisect each other and are perpendicular to each other
Given :
- Rhombus ABCD and its diagonals AC and BD bisect each other at O
- AC ⊥ BD
- AB = BC = CD = DA = 20 cm
- AC = 24 cm
Solving :
Area of the given rhombus is twice the Area of ΔABC formed by the given diagonal and two adjacent sides.
- 2 × 1/2 × OB × AC
- 24 × OB
- 24 × √AB² - AO²
- 24 × √20² - (AC/2)²
- 24 × √400 - 144
- 24 × √256
- 24 × 16
- <u>384 cm²</u>
The difference would be 589.5 degrees fahrenheit.
Answer: 11
Step-by-step explanation:
Exponential Functions:
y=ab^x
y=ab
x
a=\text{starting value = }550
a=starting value = 550
r=\text{rate = }18.8\% = 0.188
r=rate = 18.8%=0.188
\text{Exponential Decay:}
Exponential Decay:
b=1-r=1-0.188=0.812
b=1−r=1−0.188=0.812
\text{Write Exponential Function:}
Write Exponential Function:
y=550(0.812)^x
y=550(0.812)
x
Put it all together
\text{Plug in y-value:}
Plug in y-value:
60=550(0.812)^x
60=550(0.812)
x
\frac{60}{550}=\frac{550(0.812)^x}{550}
550
60
=
550
550(0.812)
x
Divide both sides by 550
0.109091=0.812^x
0.109091=0.812
x
\log 0.109091=\log 0.812^x
log0.109091=log0.812
x
Take the log of both sides
\log 0.109091=x\log 0.812
log0.109091=xlog0.812
use power rule to bring x to the front
\frac{\log 0.109091}{\log 0.812}=\frac{x\log 0.812}{\log 0.812}
log0.812
log0.109091
=
log0.812
xlog0.812
Divide both sides by log(0.812)
10.638757=x
10.638757=x
x\approx 11
x≈11
