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kakasveta [241]
3 years ago
5

The functions f and g are defined as follows.

Mathematics
1 answer:
g100num [7]3 years ago
8 0

Answer:

f(-5)=-16\\g(2)=-11

Step-by-step explanation:

By definition, a relation is a function if and only if each input value have one and only one output value.

The input values are the x-values and the output values are the y-values.

Given the function f(x):

f(x)=3x-1

You need to substitute x=-5 into this function:

f(-5)=3(-5)-1

And now you must evaluate in order to find the corresponding output value.

You get:

f(-5)=-15-1\\\\f(-5)=-16

The function g(x) is:

g(x)=-2x^2-3

Then, you need to substitute x=2 in the function:

g(2)=-2(2)^2-3

And  finally you must evaluate in order to find the corresponding output value. This is:

g(2)=-2(4)-3\\\\g(2)=-8-3\\\\g(2)=-11

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The diagram shows the curve y=(1/2x-2)^6+5. Find the area of the shaded region.
Zepler [3.9K]
So the line that is the limit is where the equation crosses the y axis or where x=0

so
y=(1/2(0)-2)^2+5
y=(-2)^2+5
y=4+5
y=9
at y=9

the upper bound is y=9

alrighty

we will do
let's call the curve that is 6th degree f(x)
and the y=9, g(x)

f(x)=(1/2x-2)^6+5
g(x)=9

find where they intersect

9=(1/2x-2)^6+5
4=(1/2x-2)^6
fancy math
x=8

so the area under the curve will be
\int\limits^8_0 {g(x)-f(x)} \, dx because g(x) is above f(x)
so

\int\limits^8_0 {g(x)-f(x)} \, dx= \int\limits^8_0 {9-((\frac{1}{2}x-2)^6+5)} \, dx=
using our calculator because I can't figure out what \int\limits (\frac{1}{2}x-2)^6} \, dx is
\int\limits^8_0 {9-((\frac{1}{2}x-2)^6+5)} \, dx= \frac{64}{3} or about 21.33333333
3 0
3 years ago
The U.S. National Highway Traffic Safety Administration gathers data concerning the causes of highway crashes where at least one
ZanzabumX [31]

Answer:

probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = 0.001932

Step-by-step explanation:

P(BAC=0|Crash with fatality)=0.625

P(BAC is between .01 and .09|Crash with fatality)=0.302

P(BAC is greater than .09|Crash with fatality)=0.069

Let the event of BAC = 0 be X

Let the event of BAC between 0.01 and 0.09 be Y

Let the event of BAC greater than 0.09 be Z

Let the event of a crash with at least one fatality = C

P(X|C) = 0.625

P(Y|C) = 0.302

P(Z|C) = 0.069

P(C) = 0.028

probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = P(C n Z)

But note that the conditional probability of probability that a driver is intoxicated (BAC greater than 0.09) given that there was a crash that involved at least a fatality is given by

P(Z|C) = P(Z n C)/P(C)

P(Z n C) = P(Z|C) × P(C) = 0.069 × 0.028 = 0.001932

Hope this Helps!!!

8 0
3 years ago
Do anybody know how to do number 16, if know can you answer it for me please, thank you!
Nutka1998 [239]


This is because using the equation provided you multiply (4140-2) by 180
Then divide it by 4140

5 0
4 years ago
Solve for x. <br><br> 6(4x+2)= 3(8x+4)
jeka57 [31]
Answer:

x = 1

Step-by-step explanation:

6(4x + 2) = 3(8x + 4)

24x + 12 = 24x + 12

x = 1
7 0
3 years ago
Read 2 more answers
Someone help me with this please
Anarel [89]

Answer:

x(x-3)(x+5)=x(x^{2}+5x-3x-15)=x^{3}+2x^{2}-15x

If something is not clear

Just ask in the comment below

Greetings from Poland :)

4 0
3 years ago
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