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3 years ago

8

A circular plate has circumference 17 inches. What is the area of this plate?

1 answer:

Nimfa-mama [501]3 years ago

7 0

Answer:

about 23 inches

Step-by-step explanation:

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Solve 2csc^2x-2cscx-1=0 <br> for 0° ≤ x ≤ 360°

umka21 [38]

Answer:

Step-by-step explanation:

2 csc²x-2 csc x-1=0

or

$\frac{2}{sin^2x} -\frac{2}{sin x} -1=0\\multiply~by~sin^2x\\2-2sin~x-sin^2x=0\\sin^2x+2sinx-2=0\\sin ~x=\frac{-2 \pm\sqrt{2^2-4*1*(-2)} }{2*1} \\=\frac{-2 \pm\sqrt{4+8} }{2} \\=\frac{-2 \pm\sqrt{4*3} }{2} \\=\frac{-2 \pm2\sqrt{3} }{2} \\=-1\pm\sqrt{3} \\|sin~x| \le ~1\\so~sin~x=-1+\sqrt{3} \\sin~x=\sqrt{3} -1\\x=sin^{-1}(\sqrt{3} -1) \approx 47.06^\circ,180-47.06\\or~x=47.06^\circ,132.94^\circ$

6 0

3 years ago

For questions 8 – 10, answer the questions about tangent-tangent angles.

olchik [2.2K]

Answer:

m(arc ZWY) = 305°

Step-by-step explanation:

8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,

Angle formed by two tangents = $\frac{1}{2}(\text{Difference of intercepted arcs})$

= $\frac{1}{2}(220-140)$

= $\frac{1}{2}(80)$

= 40°

9). Following the same rule as above,

Angle formed between two tangents = $\frac{1}{2}(\text{Difference of intercepted arcs})$

125 = $\frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]$

250 = $[m(\text{arc ZWY})-m(\text{arc ZY})]$

250 = m(arc ZWY) - 55

m(arc ZWY) = 305°

Therefore, measure of arc ZWY = 305° will be the answer.

10). m(arc BAC) = $\frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])$

= $\frac{1}{2}(254-106)$

= $\frac{148}{2}$

= 74°

4 0

2 years ago

Answers plz it’s timed

aksik [14]

Answer:

Laurie

Step-by-step explanation:

6 0

3 years ago

4. The numencal coefficient in 3xy is<br>A-3<br>В 2<br>D ху<br>Ску

BabaBlast [244]

Answer:

3

Step-by-step explanation:

Because in 3xy 3 is the numerical coefficient

3 0

3 years ago

Read 2 more answers

(2×10^6 )×(0.00009)<br><br> IN SCIENTIFIC NOTATION

pshichka [43]

In scientific notation the answer is: 0.00018 x 10^6

4 0

3 years ago