39-(15z+48)/27=35
39-35=(15z+48)/27
4=(15z+48)/27
108=15z+48
108-48=15z
60=15z
z=60/15
z=4
Let's break this up:
let x = the number
"when I triple my number" is the same as
3x
"and add five" is the same as
+5
We combine it to get
3x+5
"I get twenty-six"
=26
combine to get
3x+5=26
Now we just solve:
subtract 5 from both sides to get
3x=21
divide by 3 to get
x=7
F(-2)+g(5) = 3(-2) -1 + (-5) + 6
f(-2)+g(5) = -6 -1 - 5 + 6
f(-2)+g(5) = -6
The 4 curved white corners = 1/4 of whole circle with radius 1/2×6
total white area = 4 [1/4 (pi)(3)^2] = 9pi = 28.27
So the shaded green region (S) = total square - total white area
S = 6×6 - 28.27 = 36 - 28.27 = 7.73 sq. m
A)
is false. There is no solution.
B)
is false. There is no solution.
C)
is
true. It has infinite solutions.
D)
is
true. It has infinite solutions.
E)
is false. There is no solution.
